find dates between two given dates

[binilmb]

hi
is there any way to find dates between to given dates. ie, suppose it is given 01-01-2006 and 04-01-2006 (in dd-mm-yyyy format), want to print the dates from 01-01-2006 to 04-01-2006.

[justsomeone]

This might do the trick

// using constants to start off here, you will need to change these to wherever your dates
// are coming from

$startDate = "01-01-2006";
$endDate = "04-01-2006";

// Convert to timestamps
$startStamp = parseDate( $startDate, "%d-%m-%Y" );
$endStamp = parseDate( $endDate, "%d-%m-%Y" );

$oneday = 60 * 60 * 24;

for ($i=$startStamp+$oneday; $i < $endStamp; $i=$startStamp+$oneday){
    $inbetweenDate = date("%d-%m-%Y", $i);
    echo ($inbetweenDate."<br");
}



// This function was contributed to the PHP manual by Jae Lee
function parseDate( $date, $format ) {
   // Builds up date pattern from the given $format, keeping delimiters in place.
   if( !preg_match_all( "/%([YmdHMp])([^%])*/", $format, $formatTokens, PREG_SET_ORDER ) ) {
       return false;
   }
   foreach( $formatTokens as $formatToken ) {
       $delimiter = preg_quote( $formatToken[2], "/" );
       $datePattern .= "(.*)".$delimiter;
   }

   // Splits up the given $date
   if( !preg_match( "/".$datePattern."/", $date, $dateTokens) ) {
       return false;
   }
   $dateSegments = array();
   for($i = 0; $i < count($formatTokens); $i++) {
       $dateSegments[$formatTokens[$i][1]] = $dateTokens[$i+1];
   }

   // Reformats the given $date into US English date format, suitable for strtotime()
   if( $dateSegments["Y"] && $dateSegments["m"] && $dateSegments["d"] ) {
       $dateReformated = $dateSegments["Y"]."-".$dateSegments["m"]."-".$dateSegments["d"];
   }
   else {
       return false;
   }
   if( $dateSegments["H"] && $dateSegments["M"] ) {
       $dateReformated .= " ".$dateSegments["H"].":".$dateSegments["M"];
   }

   return strtotime( $dateReformated );
}