[RESOLVED] Need help with tables

gszauer

http://pastebin.com/606822
Dont know how long this will stay on PasteBin....
Now, as you can see, eatch image is soposed to go into a new cell, instead they all pile up in cell 1....
Can anyone help me out a bit?
Any help is appriciated.

jkarr

Can you post a link to a working example of the code? The link only displays code.

gszauer

http://yourcapecoral.com/homes.php?id=2

jkarr

If you view the source it's not all the pics showing up in one cell. It's actually each pic on it's own table row.

jkarr

your code at pastebin shows that each row will show upto 3 pics.

Make sure your pictures are in subsequent order in your table row, and not every third spot.

gszauer

Im not exatcly shure what you are saying.....
Eatch row should have 5 cells (2 blank, and 3 with pics) other than the last, and first row's...
Do you know how i could fix this?

jkarr

I'll look at it tommorow....long day at work today.

niroshan

Hi,
If im get your question right you want to display images in a table with 5 images in a row right.

Try the below code,

this code assume that you are fetching details from a database and i didnt went througn the whole coding insteed i just demostrate here only the data fetching part.

By changing the $x value in the if condition you can specify how many columns to display in a row.

if($x==2)
{
   print "</tr>";
   print "<tr>";
........

Code

$x=0;
while($result=mysql_fetch_array($row))
{	
	$imgUrl=$rootHttpPath.$result['url'];

if($x==0)
{
	print "<tr>";
}

print "    <td width=\"50%\"><div align=\"center\"><img src=\"".$imgUrl."\" width=\"342\" height=\"276\">";

print "</div></td>";

$x++;

if($x==2)
{
	print "</tr>";
	print "<tr>";
	print "     <td colspan=\"2\">&nbsp;</td>";
	print "</tr>";
	$x=0;
}
}

Hope this is what you wanted. 🙂

Regards,
Niroshan

gszauer

Yup, i think that does it, i will try the code in a it.