Url as variable -- parse error

[Oni]

Hey--

I have a small error that I've been trying to fix but can't...

I put the "\" before characters I think that would confuse Php but I can't seem to find out where to exactly put it 😛

a = "http://google.com"

:o

[duckduckgoose]

$a = "http://www.google.com";

[Oni]

😃

So long since I programmed my last code, I forgot!

Thanks