[RESOLVED] Need help to debug snippet

zzz

Thi this seems like a correctr code, but ti doesn't quite work. Can anyone see what the problem is?

foreach ($array as $key => $value) {
echo "<input type=checkbox name='".$key[i]."'";
	if ($array[i] == $key) {
		echo " checked";
	}
echo ">".$value; 
}

obsidian

zzz wrote:
Thi this seems like a correctr code, but ti doesn't quite work. Can anyone see what the problem is?

well, for one thing, you are referring to your $key as an array within the loop. i'm not exactly sure what you're trying to do with this line:

if ($array[i] == $key)

however, you should be able to echo your input boxes like this:

foreach ($array as $key => $value) {
  echo "<input type=checkbox name='' />$value";
}

if you can explain what you're checking for with the line above, we can help you implement that check as well

zzz

Yes, I am sorry, you're right. I've crossed two things. I have an array of values that should output the list of checkboxes. Also I have an array where I imploaded previous selection. So I need to see if there are any values in that saved array that correspond to the one that draws the checkboxes and if there are results that correspond -- check them.

obsidian

zzz wrote:
Yes, I am sorry, you're right. I've crossed two things. I have an array of values that should output the list of checkboxes. Also I have an array where I imploaded previous selection. So I need to see if there are any values in that saved array that correspond to the one that draws the checkboxes and if there are results that correspond -- check them.

ok, so if i understand, you have one array with the input information and another array that lists which keys should be selected. if this is correct, you should be able to do something like this:

$inputArr = array(); // create your input values here
$checkedArr = array(); // list of checked values

foreach ($inputArr as $key => $value) {
  echo "<input type='checkbox' name='$key' ";
  if (in_array($key, $checkedArr))
    echo "checked='checked' ";
  echo "/>$value\n";
}

hope this helps

zzz

Oh, I think you nailed it right on the head. Arrays are cool but I am having the hardest time with them...

zzz

Yep! Perfect.

obsidian

zzz wrote:
I am suddenly realizing that I have no idea of how to get the values from new selection and implode it for a new save...

are you talking about turning it into a string AFTER the form has been submitted? if all the checkbox fields are related, you may be better off to present them all as an array in your form. why don't you try something like this:

foreach ($inputArr as $key => $value) {
  echo "<input type='checkbox' name='myName[]' "; // notice the name
  if (in_array($key, $checkedArr))
    echo "checked='checked' ";
  echo "/>$value\n";
}

/* then, once the form has been successfully submitted */

// make sure at least one has been checked
if (isset($_POST['myName']) && count($_POST['myName']) > 0) {
  $values = implode(',', $_POST['myName']);
  echo $values;
}