problem with from processing

severndigital

Ok i am a real noob and this is my first shot at a "real" php script.

I am trying to get data from an html form and use it to build a url and then open that url.

here is what i have so far.

an html form in a seperate html file that posts to my php script.
the list menu i would like to process i have named $dkp
in my php file, I wanted to make sure it was building the url correctly so here is what i have so far.

<?php
//First set the option for the back end of the url
$urlback = 'wowguilddkp.com';

//now process the tag from the form
$urlfront = '$dkp';

//now piece it together
$url = "http://'$urlfront'.'$urlback'";

//test the output
echo "the link made by this script is '$url'";?>

when i process the form i get this as a result.

the link made by this script is http://$dkp.wowguilddkp.com

why is the php script not getting the data from the html field?

thanks to all in advance.

chris

Houdini

What is the $dkp, because you set $urlfront to $dkp so that is what it equals if $dkp has a value then do not use single quotes you need to either use doulbe quotes or no quotes at all, the single quotes tell PHP to take the term as a literal or in this case $dkp.

severndigital

$dkp is the name of the form field i am trying to extract the information from.

when i take the quotes away

$urlfront = $dkp;

the end result is an empty $urlfront field.

[url]http://.urlback.com[/url]

when it should read

http://urlfront.urlback.com

I'm sorry i don't know what i am doing, there used to be a really cool tutorial section on the site, but i can't seem to find it anywhere.

chris

laserlight

the list menu i would like to process i have named $dkp

If it is from a form, chances are you have to use $_POST['dkp']

Houdini

Well then to get whatever was set inthe form field you should use

$urlfront= $_POST['dkp'];

that is if your form method='post' or
$urlfront=$_GET['dkp']; if your form method ='get'.

severndigital

YAY!!! i got it to work. Thanks a bundle.

whoo hoo!!!!