[RESOLVED] how to display image that is in an upload directory

IceRegent

Hello again. After hours of wrangling with the code, I need a wee bit of advice on this. I have a script which allows users to upload a profile description and a picture of thier choosing. The upload and update of the database works. However, what I need to do, is figure out how to display the picture as the picture location is stored in a variable in the database. I see the location spelled out when I peek at it, but the picture displays as a broken link/missing picture. Here is the code snippet I am using:

$ProfileName = $_GET['profile'];
$query = "SELECT UserID, UserName,  password, Email, datejoin, ULevel, random, verified, profile, description, picture FROM users";
$result = mysql_query($query);
while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
  	if ($row['UserName'] == $_GET['profile'])
  	{		  			
		$Desribe = $row['description'];
		$pict = $row['picture'];
		echo '<table border="2" style="border: 2 solid #800000; padding: 1" width="70%" bgcolor="#CCCCCC">';
		echo '    <tr>';
		echo '        <td width="100%"><font face="Arial" color="#000000">UserName : &nbsp; <font face="Arial" color="#FF0000">' . $ProfileName . '&nbsp;&nbsp;' . $pict . '</td>';
		echo '    </tr>';
		echo '    <tr>';
		echo '        <td width="100%"><font face="Arial" color="#000000">UserProfile : &nbsp; <font face="Arial" color="#FF0000">' . $row['description'] . '</td>';
		echo '    </tr>';
		echo '<img border="0" src=' . $pict . '>';
		echo '<img src="http://www.iceregent.com/profiles/'. $pict . '" width="120" height="94" border="0" alt="">';
		echo $pict;
		echo '<p><span style="position: absolute; left: 1; top: 0"><img border="0" src="' . $pict .'" width="95%" height="90"></span></p>';
	}
}
?>

I have setup 3 different attempts to display the picture in the last of the code. All three attempts make the box with the red 'X' in them. What am I doing wrong? The file is successfully uploaded into the correct directory called 'profiles' .

Below is the output I get, of course, you cannot see the red 'x' boxes..:

UserName : popeye popeye.jpg
UserProfile : this is a test of the profile update
popeye.jpg

Can anyone see what I am doing wrong?

thank you
Ice

dinger

IceRegent wrote:
Hello again. After hours of wrangling with the code, I need a wee bit of advice on this. I have a script which allows users to upload a profile description and a picture of thier choosing. The upload and update of the database works. However, what I need to do, is figure out how to display the picture as the picture location is stored in a variable in the database. I see the location spelled out when I peek at it, but the picture displays as a broken link/missing picture. Here is the code snippet I am using:
$ProfileName = $_GET['profile'];
$query = "SELECT UserID, UserName, password, Email, datejoin, ULevel, random, verified, profile, description, picture FROM users";
$result = mysql_query($query);
while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
 	if ($row['UserName'] == $_GET['profile'])
 	{		 			
		$Desribe = $row['description'];
		$pict = $row['picture'];
		echo '<table border="2" style="border: 2 solid #800000; padding: 1" width="70%" bgcolor="#CCCCCC">';
		echo ' <tr>';
		echo ' <td width="100%">UserName : &nbsp; ' . $ProfileName . '&nbsp;&nbsp;' . $pict . '</td>';
		echo ' </tr>';
		echo ' <tr>';
		echo ' <td width="100%">UserProfile : &nbsp; ' . $row['description'] . '</td>';
		echo ' </tr>';
		echo '<img border="0" src=' . $pict . '>';
		echo '<img src="http://www.iceregent.com/profiles/'. $pict . '" width="120" height="94" border="0" alt="">';
		echo $pict;
		echo '<img border="0" src="' . $pict .'" width="95%" height="90">';
	}
}
?>
I have setup 3 different attempts to display the picture in the last of the code. All three attempts make the box with the red 'X' in them. What am I doing wrong? The file is successfully uploaded into the correct directory called 'profiles' .

Below is the output I get, of course, you cannot see the red 'x' boxes..:

UserName : popeye popeye.jpg
UserProfile : this is a test of the profile update
popeye.jpg

Can anyone see what I am doing wrong?

thank you
Ice

What directory are the pics in?

Are they in the root directory of the site?

Are they in the /profiles/ directory?

http://www.iceregent.com/profiles/popeye.jpg is the URL of the pic it would load in your example.

If the pics are in another directory (which it seems may be the problem) you need to specify that in your URL.

IceRegent

the pictures are being uploaded, and correctly, to the /profiles/ directory, such as in :

http://www.iceregent.com/profiles/popeye.jpg

I first manually placed a file in there, and tried to display it, but I cannot thru the php code. Then, I tried using a jpg file that I uploaded thru the form, and it still wont display.

Ice

dinger

IceRegent wrote:
the pictures are being uploaded, and correctly, to the /profiles/ directory, such as in :

http://www.iceregent.com/profiles/popeye.jpg

I first manually placed a file in there, and tried to display it, but I cannot thru the php code. Then, I tried using a jpg file that I uploaded thru the form, and it still wont display.

Ice

When i click on that link Firefox says it cant display the image because it contains errors:

The image “http://www.iceregent.com/profiles/popeye.jpg” cannot be displayed, because it contains errors.

I really have no idea what this means because ive never seen this error before.

Perhaps it was uploaded incorrectly? Maybe the image was uploaded as ASCII not Binary? I really have no idea...

IceRegent

Ok, after a little investigation, I too found that error message, and upon going back, I discovered that something about that set of pictures was not created by photoshop correctly. I opened the picture in MSPaint, and resaved it as a new jpg, and then went thru the upload script process, and now it works well. Sheesh, all that head scratching and it turns out some quirck with photoshop is causing my headaches.

But now, how do I make sure that my users are limited to a certain size of picture upload? I dont want them to be able to upload a 500 x 500 pixel picture. How do I set and check on the picture size in my upload script?

Thanks

Ice

dinger

I think you would have to check the size of the image using the gd() library.

Don't quote me on that though.

tbobker

try taking the size of the image out in the <img> tag, i had a problem and i took it out and for some reason it worked!