mktime php 5

[online]

Before, i use php 4., and now my host company go to php5!

Before was ok (the code script), but now...i get this error:

Warning: mktime() expects parameter 6 to be long, string given in ...
(i use in code the 4 digits format - Year)

[bradgrafelman]

Show us this line of code... though it's rather obvious what you did. Sounds like you surrounded the year in quotes, or used some non-numeric format.

[online]

function ifNew ($date)



{



global $def_new;



$date_day = date ( "d" );

$date_month = date ( "m" );

$date_year = date ( "Y" );



list ( $on_year, $on_month, $on_day ) = split ( '[/.-]', $date );



$first_date = mktime ( 0,0,0,$on_month,$on_day,$on_year );

$second_date = mktime ( 0,0,0,$date_month,$date_day,$date_year );



if ( $second_date > $first_date )



{



	$days = $second_date - $first_date;



}



else



{



	$days = $first_date - $second_date;



}



$current_result = ( $days ) / ( 60 * 60 * 24 );



if ( $current_result <= 5 )



{



	$new_listing = "$def_new";



}



else



{



	$new_listing = "";



}



return $new_listing;



}

[bradgrafelman]

Yikes, try to cut down on the whitespace when you post code.

Also... which line is the error referring to? The first call to mktime or the second?

[online]

The first and the second one! 🙂 It show me 2 errors!

[HalfaBee]

Have you tried echoing out the variable causing the problem?
Most likely a character at the begining of the number is causing the problem.

[online]

The problem is: $on_year and $date_year (the php said that are only with 2 digits-the year format)!

But i echo $date_year ($date_year = date ( "Y" ); ) and it was ok..4 digits!

The problem is when i run the code... I don't know why!

[laserlight]

Basically, you just want to find the difference between the date entered and the current date?

function ifNew($date, $def_new)
{
	list($year, $month, $day) = preg_split('#[/.-]#', $date);
	$date_stamp = mktime(0, 0, 0, $month, $day, $year);

if (abs($date_stamp - mktime(0, 0, 0)) <= (60 * 60 * 24 * 5))
{
	return $def_new;
}
else
{
	return "";
}
}