parse error, cant find the problem

[bigfooot]

  $junk = array('.' , ',' , '/' , '\' , '`' , ';' , '[' ,  ']' , '-',
              '*', '&', '^', '%', '$', ', '@', '!', '~', '+', '(', ')', 
			  '|', '{', '}', '<', '>', '?', ':', '"', '='); 

I get the following error:
Parse error: parse error, expecting `')'' in (blah blah) on line 20

line 20 is the first line in the code i submited. Can anyone help me here?

I am following the tutorial from http://www.allsyntax.com/tutorials/PHP/26/Complete-Members-System/1.php

BTW i have php version 4 if it makes a difference.

thanks in advance
alex

[cdwhalley_com]

Your array:

 $junk = array('.' , ',' , '/' , [b]'\'[/b] , '`' , ';' , '[' ,  ']' , '-','*', '&', '^', '%', '$', ', '@', '!', '~', '+', '(', ')','|', '{', '}', '<', '>', '?', ':', '"', '='); 

If you look where I made it bold - a \ before a ' or a " in PHP means to 'escape' it, in other words - to get rid of its special meaning in PHP. What you have done where I have made it bold is with the \ you have escaped the ' that closes that element of the array, so that part of the array continues until the next ' after the , - and throws the rest of the array one step forward and out of kilter.
Try putting '\' in the array for that element...
From the PHP manual:

The backslash character has several uses. Firstly, if it is followed by a non-alphanumeric character, it takes away any special meaning that character may have. This use of backslash as an escape character applies both inside and outside character classes.

For example, if you want to match a "*" character, you write "*" in the pattern. This applies whether or not the following character would otherwise be interpreted as a meta-character, so it is always safe to precede a non-alphanumeric with "\" to specify that it stands for itself. In particular, if you want to match a backslash, you write "\".

[Installer]

Here's the part of the manual that applies here:

Single quoted
...If a backslash needs to occur before a single quote or at the end of the string, you need to double it. Note that if you try to escape any other character, the backslash will also be printed! So usually there is no need to escape the backslash itself.

And take a look at this sequence:

'$', ', '@',

[Houdini]

This is a good reason for having an editor that highlights code, last week there was a similar question with the identical data and same backslash error, and since it is a tutorial then unless the author is trying to let users know not to do that then there needs to be a way of letting him know that his tutorial needs fixing.

The array name$ junk and all chars in the array were identical and actually just by posting it here in these forums showed the error rather quickly. So I then ran it through an editor and found the best way to prevent errors was with double quotes other wise you also has a single quote with single quotes so this will work

<?php
 $junk = array("." , "," , "/" , "\\" , "`" , ";" , "[" ,  "]" , "-",
              "*", "&", "^", "%", "$", ",", "@", "!", "~", "+", "(", ")",
              "|", "{", "}", "<", ">", "?", ":", "'", "=");
echo "<pre>";
print_r ($junk);		   

?>