code help

robmann

Not sure what is wrong here

    print " | <a href='#comments' onclick='window.open(\"comments_edit.php?comments=".$row->ID."\", \"TheWindow\", \"height=400,width=500\")'>Edit</a>";
  print "<br><br>$row_front&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;".str_replace("\n","<br>$row_front&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;",wordwrap(htmlentities($row->comment), 120-($row_num*6), "\n"))."</div><br> \n";

when I open comment_edit.php I get

Warning: mysqli_error() expects exactly 1 parameter, 0 given in /home/jsuspens/public_html/shimprogram/VDB/Free_/comments_edit.php on line 10

line 10 is

$result=mysqli_query($dbc,"SELECT * FROM comments WHERE ID=$comments AND login_id=$login_id".mysqli_error());

anyone see my error?

devinemke

pretty self expanatory error message. the manual page on [man]mysqli_error[/man] explains that the function takes a mysqli resource link as it 1 (and only 1) argument.

bradgrafelman

Why are you trying to append the MySQL error message to the query sent to the database...?

robmann

I did not write the code originally but I know have to figure it out and make changes to it because I moved everything to a PHP 5 server, if anyone has a better way to rewrite what is there I will take any suggestions

bradgrafelman

Well, if you don't have your own error handler...

$query = "SELECT * FROM comments WHERE ID=$comments AND login_id=$login_id";
$result = mysqli_query($dbc,$query) or die('Error - MySQL said: ' . mysqli_error($dbc));