Is $_SESSION accessible from CLI PHP?

ppowell

Is it possible to access values preset from $SESSION from within a CLI PHP page? If so, how is it done? Each time I try to access $SESSION is an empty array; the moment I leave the CLI PHP and return to my calling web-app PHP script, $_SESSION is back again, values and all, completely untouched.

Can $SESSION be called? If not, then I have a bigger problem inasmuch as $REQUEST variables set via form/query-string MUST be accessed from within CLI PHP script, and the only way I can think of is to put all of $REQUEST into $SESSION, or what else do I do? Stumped.

Thanx
Phil

scrupul0us

what are u trying todo via CLI with PHP?

could always store store the stuff in a DB or flat file and get em that way

ppowell

I may have to (DB that is), or a serialized throwaway file, provided no disconnect occurs.

Here's the deal: I have a web app whereby the entire query is stored in a CLI PHP (due to its enormous run time because it's that monstrous a query!!), however, recent requirement stipulated that this monstrous query be filtered according to form actions (like you select a state, a city, a date, etc. and click FILTER). I can't use $REQUEST because $REQUEST becomes completely different in CLI PHP (turns into $argv instead), so I have to preserve the values in $REQUEST somehow and I thought I could do so in $SESSION, but the CLI PHP keeps telling me $_SESSION is an empty array, when in fact it's not (this proving by doing print_r() before and after the CLI PHP and it's intact!)

Phil

bradgrafelman

Of course $_SESSION is empty... think about it:

PHP opens previous sessions based on the SID your browser passes via a cookie/URL/form element/etc.

If you're running PHP from the command line... you're not sending HTTP headers (cookies) or sending a form or anything. Why would it know what session you're talking about?

If you want to pass params to the CLI, then argv is the way to go.

ppowell

I decided to go the DB route instead, however, having another problem, back to square one:

I have this table:

CREATE TABLE /! IF NOT EXISTS / php_filter_request_array_holder (
ip varchar(20) not null,
unique (ip),
data text
) /! TYPE=MyISAM /;
]/Quote]

How on earth do I select via the CLI PHP:
if (!is_object($dbAP)) $dbAP =& new DBActionPerformer();
   if (!$dbAP->getDBConn()) @$dbAP->connect();
   $sql = "SELECT `data` FROM php_filter_request_array_holder WHERE ip = '" . mysql_escape_string($_SERVER['REMOTE_ADDR']) . "' LIMIT 1";
   print_r($sql); print_r("<P>\n");
Which of course prints:

SELECT data FROM php_filter_request_array_holder WHERE ip = '' LIMIT 1

Because, of course, $SERVER doesn't exist for $SERVER['REMOTE_ADDR'] to exist (which makes sense from a web security standpoint, but it doesn't help me one bit!)

Help!

Phil

bradgrafelman

Then send the user's IP in the query string when you make the call to the CLI, i.e.

exec('/usr/bin/php /path/to/yourscript.php?ip=' . $_SERVER['REMOTE_ADDR'] . ' &');

Then use $argv to get it from the "URL" of the script executed from the CLI.

ppowell

print_r(is_file('/home/me/cli.php?ip=' . $_SERVER['REMOTE_ADDR'])); // PRODUCES NULL

Sorry, it can't find the file with a query string attached.. I gave up and added a seventh argument into the very long exec

Phil

bradgrafelman

Woops, my mistake. Try something like::

exec('/usr/bin/php /home/me/cli.php variable1=value variable2=value');

And you should be able to use $_GET['variable1'] and such.