PHP rendered differently from mysql db

ndorfnz

Here's the deal...

I have a php function that I call:
<? imagesize('image.jpg','image text'); ?>

at the end of the php function some javascript outputs a link based on some dynamic variables established from the function.

When I simply do this within my php page works great!!! :rolleyes:

However, when the function call is extracted from a mysql data field, it does NOT render?

For example...when rendered via my .php page (this is correct!):
<a href="javascript:showimage('image.jpg','511','343')">image text</a>

When rendered html via .php from mysql table query:
<? imagesize('image.jpg','image text'); ?>

What's happening that causes these to work differently?

Isn't the output from the mysql getting rendered as php/html the same way?

Thanks much!

ndorfnz

It looks as if eval is what I need to use...

However, struggling horribly with this! :glare:

How do I get the php function to run using eval?

<? eval(imagesize('image.jpg','image text')); ?>

Appreciate some guidance, been reviewing many a posts on other eval(), but none really pointing towards a php function call within eval()

Weedpacket

The function call isn't evaluated when pulled out of the database because it's just a string. PHP doesn't search through every string on the off-chance that it might contain PHP code (which is a Very Good thing for these forums - imagine what could happen if it did).

eval() expects a string containing a valid PHP statement (being a function call or not is not important - having valid PHP syntax is). So you're almost there.

<? eval("imagesize('image.jpg','image text');"); ?>

Note the quotes, and the semicolon. If the string returned from the query is "imagesize('image.jpg','image text');", then you're done.

ndorfnz

Ok, here's what gets returned now:

<? eval("imagesize('image.jpg','image text');"); ?>

I see this in the view source of my page.

I have seen some posts regarding use of ?> <?php, but don't quite grasp it. Could this be the other problem?

Thanks much!

Houdini

<? vice <?php is referred to as a short tag and unless short tags are turned on with the server you are using they will not work. It is better to not use them at all so merely add php to the <? so it looks like <?php then it might just solve your problem on that server.

Weedpacket

PHP used to use <?, but when XML came along and starting using that for processing instruction tags, PHP switched to using <?php and <? was made optional (for the sake of all that older code out there). As the manual says, <?php will work in any PHP configuration, <? might not.