Says its an array, when shouldnt?

WinterDragon

Hard to summarize this problem in the title, but I can try better here..

Alright, I have a multi-select form item, with 4 items. Now, in the code (using ajax, but using xajax class, which shouldnt matter). So here is the HTML code..

<select name="armortypes[]" multiple="yes" size="4">
<option value="cloth">Cloth</option>
<option value="leather">Leather</option>
<option value="chain">Chain</option>
<option value="plate">Plate</option>
</select>

Simple right? Well lets go onto the PHP code..

$counter = 0;

if(is_string($armortypes)) {
        if(isset($equip_slot) || isset($class)) {
                $query .= " AND (";
        } else {
                $query .= " (";
        }
        $data .= "(armortype='" . $armortypes . "') ";
} elseif(is_array($armortypes)) {
        if(isset($equip_slot) || isset($class)) {
                $query .= " AND (";
        } else {
                $query .= " (";
        }
        foreach($armortypes as $i) {
                $query .= "armortype='" . $armortypes . "' ";
                if(($counter + 1) == count($armortypes)) {
                        $query .= ")";
                } else {
                        $query .= " OR ";
                }
                $counter++;
        }
}

if I select one item, it still shows up as it being an array (it apparently passes the is_string test, but then when its printed out, says Array)... I'm not sure whats going on, the other 2 multi-select menus in the form work fine... this is the one that doesnt... am Id oing something wrong? Thanks for any help..

Shrike

Since the select field is named with a '[]' it will always be an array in PHP. How are you getting the variable $armortypes? Perhaps if no options are selected when the form is submitted, your code is turning $armortypes into a string?

WinterDragon

Thats not really true, having '[]' will return arrays if multiple items are selected, and a variable if just one is selected (proven by my other two multi-select fields). Also I am getting armor types like... this..

<?php
function searchFor($formValues) {
        $objResponse = new xajaxResponse();
        $equip_slot = $formValues["equip_slot"];
        $class = $formValues["class"];
        $armortypes = $formValues["armortypes"];
        $objResponse = new xajaxResponse();
        $objResponse->addAssign("results", "innerHTML", $data);
        return $objResponse;
}
$xajax = new xajax();
$xajax->registerFunction("searchFor");
$xajax->processRequests();
?>

its using xajax, but the other multi-selects, and gathering information etc, works just fine, and I've not changed anything.

Shrike

I guess you know better than the PHP manual then.

The solution is to use PHP's "array from form element" feature. The following should be used: <select name="var[]" multiple="yes">

This tells PHP to treat $var as an array and each assignment of a value to var[] adds an item to the array. The first item becomes $var[0], the next $var[1], etc.

http://uk.php.net/manual/en/faq.html.php#faq.html.select-multiple

I suggest you add some lines to debug:

print_r( $formVariables );
echo gettype( $formVariables['armortype'] );

In the Ajax callback function and see what is happening.

WinterDragon

Strange enough, because I used this method (shown above) in the previous two multi-select menus.. this was the only one causing me a problem.. So why is this strangely different?

WinterDragon

I decided since 2 of them worked and one didn't, I am changing the code to use count() to see if the array is 1 or more, and do whatever is needed. shrugs.

WinterDragon

and by the way... its returning "NULL" as the type. No matter if i select multiple, or only one in that specfic multi-select menu. Ah well, after a bit of reprogramming, it all works now.