while loop conditionS

[toshog]

so it's not possible to have more than one condition in a while loop?! like:

while($row = mysql_fetch_array($result) && $moo = true)

or

while($row = mysql_fetch_array($result) && $moo < 10) $moo++;

[Kardall]

no, but you could do a simple thing like:

while($row = mysql_fetch_array($result)) {
  if($moo == false) {
    // do something
  }
}

[etully]

This works for me:

$x=0; $y=15;
while ($x<10 and $y<20) {
print "($x,$y)\n";
$x++; $y++;
}
print "loop done\n\n";

In your first example, you wrote "$moo = true". Shouldn't that be double equal signs? I'm not sure why your second example isn't working.

[codeordie_com]

It must be evaluated this way:

while(($row = mysql_fetch_array($result)) && $moo == true)

I think that's the problem (==) ($moo is true always because you are assigning a value, not comparing them).
You can have more than one condition, but ... has your $result any row?

$i = 0;
if ($i = 0)
	echo "0 is false. This echo is never printed.";
if ($i == 0)
	echo "$i equals 0";

Hope this helps,