[RESOLVED] Variable Scope

[obrienkev]

Hi all,

Why do the variables lose their values after the error checking?
Thanks.

if(isset($_POST['submit']))
{
// set variables		
$fund_number = $_POST['fund_number'];
$res = trim($_POST['res']);
$name = trim($_POST['name']);

// declare an empty error array
$error_message = array();

/*************************
   Form Error Checking
*************************/
     if(!$res || $res = '')
     {
        $error_message['res'] ='Please Enter Suggested Resolution';
     }
     if(!$name || $name = '')
     {
        $error_message['name'] ='Please Enter Your Name';
     }
/*********************************
 If No Form Errors
*********************************/

[laserlight]

Which variables lose their values?

[thorpe]

Because your assigning them an empty string.

$res = ''

Should be...

$res == ''

[laserlight]

By the way, I suggest that you check the incoming variables, not the variables that the incoming variables' values have been assigned to.

if (isset($_POST['submit']))
{
	// set variables
	if (isset($_POST['fund_number']))
	{
		$fund_number = $_POST['fund_number'];
	}
	else
	{
		// serious error?
	}

// declare an empty error array
$error_message = array();

// Form Error Checking
if (empty($_POST['res']))
{
	$error_message['res'] = 'Please Enter Suggested Resolution';
}
else
{
	$res = trim($_POST['res']);
}
if (empty($_POST['name']))
{
	$error_message['name'] ='Please Enter Your Name';
}
else
{
	$name = trim($_POST['name']);
}

// ...
}

[obrienkev]

Thanks guys. Double = was the problem.