side menu help, please

[bufhal]

I hope someone can help me figure this out..

My side menu is attached to a MySQL database and the very bottom link "Testing" will only appear when there is an item stored in the DB.

Here is a test page:
http://www.attotech.com/new_side_menu_test.html

Here is the side menu code:
<?php
if ($url15 != "") {
echo "<a class=\"item3 arrow\" href=\"javascript:void(0)\">More Information";
echo "<img src=\"/images/arrow3.gif\" width=\"10\" height=\"12\" alt=\"\" /></a>\n";
echo "<div style=\"border: 2px; #FFFFFF\" class=\"section\">\n";
echo "<a class=\"item2\" href=\"$url15_url\">$url15</a>\n</div>\n";
}
?>
I am trying to get "More Information" to display what is in the url13 field of the database. In other words, I want to be able to change the wording for "More Information" in the database if that field is showing(when url15 and url15_url are populated.)

I appreciate any help..please let me know if you need further information.

Thank you

[guigrrl]

Have you tested to see if $url13 will come up outside the "if ($url15 != "") { ..." condition?

[bufhal]

Thanks for the reply, guigrrl

I tried to incorporate the url13 into the PHP but keep getting parse errors. I am somewhat new at PHP and am unclear what and where...

I appreciate any help.

[guigrrl]

Is that the only code you have?
Are you pulling the data from the database?

If you've tested and your db connections is working, you can test by entering:

echo"$url13";