[RESOLVED] reading a file, as if it was uploaded

[perpetualshaun]

Let's say that I have a form w/ a file field of upload. So when I copy the file to a directory on the server, I copy the $FILES['upload']['tmp_name']. For this application, I would like to re-define that variable w/ another file out on the server. So how could I define the $FILES['upload']['tmp_name'] to equal the appropriate part of a file out on the server; something like /images/test_image.jpg?

[devinemke]

i don't quite understand the question. you are just trying to copy the uploaded file?

copy($_FILES['upload']['tmp_name'], '/images/test_image.jpg');