amount of files in a folder

[error_22]

Hello,

I need a script that checks for the amount of files in a folder. Is taht possible with PHP, and if so, how?

Thanks in advance

Niklas

[daxxy]

The one I'm working on to display files with paging shows how many files are in a folder. your welcome to use it..

[error_22]

and it can be found where?

[leatherback]

A simple solution would be to use the [man]readdir[/man] function, an that page there is an example:

<?php
if ($handle = opendir('.')) {
   while (false !== ($file = readdir($handle))) {
       if ($file != "." && $file != "..") {
           echo "$file\n";
       }
   }
   closedir($handle);
}
?> 

when modified looks like:

$count = 0;
if ($handle = opendir('.')) {
   while (false !== ($file = readdir($handle))) {
       if ($file != "." && $file != "..") {
           $count++;
       }
   }
   closedir($handle);
}

echo "Number of files in dir: ".$count;

[daxxy]

The script is

<?php 
if(!$_GET['start']) { 
$start = 0; 
} else { 
$start = $_GET['start']; 
} 
$exclude_files = array(""); 

$ifiles = Array(); 
$handle = opendir('.'); 
$number_to_display = '9'; 
while (false !== ($file = readdir($handle))) { 
   if ($file != "." && $file != ".." && !in_array($file, $exclude_files)) {   

sort ($ifiles);
       $ifiles[] = $file; 
   } 
} 
closedir($handle); 

$total_files = count($ifiles); 
$req_pages = ceil($total_files/$number_to_display); 

echo "total files = ". $total_files."<br>"; 

   for($z=0; $z<$number_to_display; $z++) { 
       //$vf = $z+($start+$number_to_display); 
	$vf = $z+$start;       

if ($ifiles[$vf] != "") 
echo "<a href=\"". $ifiles[$vf]. "\">".  $ifiles[$vf] . "</a>\n"; 

  echo '<br>'; 
} 
echo "<br>Req Pages = ". $req_pages. "<br>"; 
echo "<a href=\"?start=0\">First</a> |"; 
   for($x=0; $x<$req_pages; $x++) { ?> 
<a href="?start=<? echo $x*$number_to_display; ?>"><? echo $x+1; ?></a> | 

<? } ?> 

<a href="?start=<? echo ($x-1)*$number_to_display; ?>">Last</a> | 

just put it in the folder you want to read

you can change or add separated by commas

$exclude_files = array("whatever file or folder");

whatever number you want on each page
$number_to_display = '9';

[error_22]

is there a way to limit so it only counts a certain file ending? such as .jpg, or perhaps check the amount of files and substract with a number?

Thanks

[benbox]

Modifying what leatherback posted: -

$count = 0; 
if ($handle = opendir('.')) { 
   while (false !== ($file = readdir($handle))) { 
       if ($file != "." && $file != "..") { 
           $split = explode(".", $file);
           if($split[1] == "jpg") {
                 $count++; 
           }
       } 
   } 
   closedir($handle); 
} 

echo "Number of files in dir: ".$count; 

You can change that if($split[1] == "jpg") { line to whatever filters you want.. such as

if($split[1] == "jpg" || $split[1] == "gif" ) {

would find jpg's and gif's

[thorpe]

 $count = 0;
if ($handle = opendir('.')) {
   while (false !== ($file = readdir($handle))) {
       if (substr($file,-4,4) == ".jpg") {
           $count++;
       }
   }
   closedir($handle);
}

echo "Number of files in dir: ".$count;