Two different actions for one select menu

thefinerminer

How can you make a form with only one drop menu go to different php pages based on what is selected from the list? I know how to pass the selected value, but I can only set one action attribute per form. I've seen how to do this for multiple submit buttons, or mutiple check boxes, but I can't find how to do it based on the selection. (I don't want multiple selections).

All I want is 5 options to go to one php page, and 4 to go to the other.

Putting action="page.php" in the form tag obviously goes to the same place for all options. Can I insert some code into the option tags, or should page.php act as another redirect based on the submitted value, or is this a job for if else in javascript?

Any help appreciated!

Damien

The_Chancer

send it to a PHP page, with something like

switch ($_POST['somevar'])
{
case ("1","2","3","4","5"):
require("thisfile.php");
break
case("6","7","8"):
require("anotherfile.php");
break;
}

Should help...

iNFERiON

You could do this.

<?php
// example.php
if(isset($_POST['target'])) {
$target = strtolower($_POST['target']);
header("Location: " . $target . ".php");
}
?>
<form method="post" action="example.php">
<select name="target">
<option>Test</option>
<option>Another</option>
</select>

A menu like that would take you to either test.php or another.php.

thefinerminer

Wow...thanks guys. I had no idea you'd reply so fast. Both methods work...I spent several days banging my head against walls before I stumbled across this site. Thanks again.

Damien