in_array error

[Darien_Shields]

I can't understand what's going wrong when I call this script;

function move($direction)
{
	if (in_array($direction, $position["exits"]))
	{
		$position = $position["exits[$direction]"];
		echo $position["enterdescription"];
	}
	else
	{
		echo "<P>You can't go that way from here.</P>";
	}
}

I get the error "
Warning: in_array(): Wrong datatype for second argument in /home/content/D/a/r/DarienShields/html/test/map.php on line 9"

It's called as "move("NORTH")" and $position should have been set to this array;

$lobby = array("name" => "lobby", "lookdescription" => "<P>You are in the lobby of a mansion. You can go North (N), East (E), South (S), or West (W)</P>", "enterdescription" => "<P>You return to the lobby</P>", "exits" => array("NORTH" => $north, "EAST" => $east, "SOUTH" => $east, "WEST" => $west));

Any help would be much appreciated, I'm already extremely thankful for all I've been told.

[ClarkF1]

Try:

$position = $position["exits"][$direction];

[Darien_Shields]

ClarkF1 wrote:

Try:

$position = $position["exits"][$direction];

No good. The problem, I think, is with the "in_array" bit. It says that the second argument is invalid, but I thought the second argument was an array, just like it wanted.

[laserlight]

First, take a close look at this line:

function move($direction)

This means that the move() function has one argument, $direction.

Now take a look at this line in the move() function:

if (in_array($direction, $position["exits"]))

Where does $position come from? It doesnt exist in the function.

[Darien_Shields]

Gah, there were lots of problems with it, but I got some help from a friend and it works now.

Sorry for the rather incoherent garble of code.

[halojoy]

well,
I was just about to try to help to sort out that code
.. but just as good i wont have to .. it was a bit strange in some places
🙂