[RESOLVED] Joining two variables to make one?

schwim

Hi there guys,

Sorry for the rediculously simple question, but my Super-Duper Sam's book doesn't seem to have the answer, and I'm not doing so well at finding it in the php manual.

I'm making a login search script where someone has to enter two characters in one box then a 6 digit number in another box. On the results page, I'm trying to get those two variables to make one:

$initials=js
$digits=000000

should make:

$result=js000000

I've tried

$result=($initials,$digits);
$result=(($initials)($digits));

And a lot of other things, but it's obvious that I didn't do it right because I keep getting a lot of different errors.

Can someone help me figure out how to merge two variables into one?

Thanks very much for your time,
json

Drakla

use a dot instead of a comma in your first example

schwim

thank you very much for your reply. It got rid of the error, but when I try to print the result, I'm not getting anything.

It's coming from a form(method post), and I tried:

$result=($_POST[initials].$_POST[digits]);
echo "result is ".$result.".";

But I still get a blank where the result should be. Again, I'm sorry for the ignorant questions.

thanks,
json

thorpe

Your code should work, however, there is no need for the barckets, plus you really should surround non numeric array indexes with quotes.

You might also want to check that the $POST variables in question are actually set.

if (isset($_POST['initials'], $_POST['digits'])) {
    $result = $_POST['initials'].$_POST['digits'];
    echo "result is ".$result.".";
} else {
    echo '$_POST values not set';
}

schwim

Solved.

I'm such a freaking moron.

I needed to update the form to reflect the changed variables.

Sorry for the trouble guys.

thanks,
json

schwim

ok, I understand(I think). Your code not only will show me the variable(if it exists), but also if the variables haven't been passed from the submission form, right?

Wow, thanks very much for that!

thanks,
json