Test string for proper alphanum format

[badboy2]

I want to test a string for proper apha numeric formatting such as :
$my_string=1FUD567894; 1 numeric, 3 alpha, 5 numeric.

Tried this code but something is not quite right:

if (!ereg("^{(([0-9]{0,1})+([A-Z]{2,4})+([0-9]{5,10}))$",} $my_string)) {
echo "Wrong format";
} else {
echo "Pass test";
}

Thanks,
BB

[madwormer2]

^{((\d)([A-Z]{3})(\d{5}))$}

That should work.

\d matches any number, so is essentially the same as [0-9].

In your pattern, you use + to the effect that you believe it will "AND" it, but in fact this character actually means the same as {1,} which is match "ONE OR MORE" of the thing in brackets before it.

[badboy2]

^{((\d)([A-Z]{3})(\d{5}))$} is still echoing "Wrong format"

Perhaps I should clarify the question, I need to test the format meaning the exact sequence: 1 numeric then 3 alpha then 5 numeric !

[madwormer2]

Actually, use preg_match:

$my_string="1FUD567894";
preg_match("/(\d[A-Z]{3}\d{5})/i", $my_string);

[cgraz]

The following works for me:

<?php

$var = '1FUD567894';

if( preg_match('/^([0-9]{1})([A-Za-z]{3})([0-9]{6})$/', $var) )
{
	print "Match Found";
}
else
{
	print "Match Not Found";
}

?>

I changed 5 numeric at the end to 6 because your post had 6 numeric at the end. If you want 5 instead, just change the {6} to {5} and adjust the test $var or it will return Match not Found (maybe why your earlier tests were not working. Looking to match 5 ending numeric characters but the string you were using to test had 6)

[laserlight]

I think you will find this simpler:

<?php
$str = '1FUD567894';

if (preg_match('/^\d[A-Za-z]{3}\d{5}$/', $str)
{
	echo 'Match';
}
else
{
	echo 'No match';
}
?>

Note that this should print 'No match', since '1FUD567894' has one more numeric character at the end compared to your requirements, as what cgraz pointed out.