Storing index value from dynamic select menu in db

[clubbedougan]

This code is part of an Edit Item page which defaults to the previous selected catalogue, however, I want to insert the approproriate number for each instance. For example, the first will be 1 the second 2 and so on.

Seems simple enough, but I've had no luck storing the index value in the database.

It only seems to want to insert the text of it, however, I want to insert '1' if A / W 2006 is chosen, 2 if S /S 2007 is chosen , etc.

<p><b>Catalogue :</b><br /> 
    <select name="catalogue" size="1"> 
    <option></option> 
    '."\n"; 

$catalogues = array('Autumn / Winter 2006', 'Spring / Summer 2007', 'Autumn / Winter 2007', 'Spring / Summer 2008', 'Autumn / Winter 2008'); 

for($i = 0, $j = count($catalogues); $i < $j; $i++){ 
    echo '<option value="'.$catalogues[$i].'"'.(($catalogues[$i] == @$row[6])?' selected="selected"':'').'>'.$catalogues[$i].'</option> 
    '."\n"; 
} 
echo '    </select></p> 

Currently I'm using $catalogue = $_POST['catalogue']; then putting it in the SQL query, but it only takes the text. How do I get the relevant index no?

Thanks for any suggestions!

[HeyRay2]

    foreach($catalogues as $index=>$value){
         echo '<option value="'.$index.'"'.(($index == @$row[6])?' selected="selected"':'').'>'.$value.'</option>
        '."\n"; 
    }

[clubbedougan]

Many thanks for your swift reply.

However, I have just found another soluion which works just the same.

Thanks again for your efforts.