Processing several checkboxes (checked and unchecked) to array

Dude0

Hello,

I have two questions about form processing with checkboxes.

With the code

<input type=checkbox name=list[] id=list[]> X
<input type=checkbox name=list[] id=list[]> Y

[] X
[] Y

If only X is chosen then the array has only one element

[0] = on

What I need is that all the elements are there with on or off

[0] = on
[1] = off

Is this possible?

The other question is

how can it be done so that the array index is a name, so the results look like

[x] = on
[y] = off

Thanks.

sneakyimp

i'm not sure if you can get all of the checkboxes to have a valued defined even if they are unchecked. you might have to put a pair of radio buttons for each one:

<INPUT type="radio" name="list[x]" value="on">on
<INPUT type="radio" name="list[x]" value="off">off

if you don't mind certain checkboxes having nothing defined if they are not checked, you can do this:

<input type=checkbox name=list[x] id=list[]> X
<input type=checkbox name=list[y] id=list[]> Y

this MIGHT work for you:

<input type="hidden" name="list[x]" id="list[x]" value="off">
<input type="checkbox" name="list[x]" id="list[x]" value="on"> X
<input type="hidden" name="list[y]" id="list[y]" value="off">
<input type="checkbox" name="list[y]" id="list[y]" value="on"> Y

I'm not sure that it would be reliable though.

bogu

Another idea would be to have an array with all the checkboxs that should come after submitting, if the checkbox come on POST after submitting then that checkbox is "on" else that box is "off", but I still don't know why do u need that ...

Weedpacket

I'd go along with what bogu suggested: you know what checkboxes are in the form, and you know which ones are checked because they're in the submitted results. Those two pieces of information are enough for you to figure out which checkboxes in the form weren't checked...

Give them distinct values (x, y, or whatever you're using), instead of just "on" or "off", because "on" or "off" wouldn't tell you anything you couldn't already figure out by just seeing whether they were there or not.