My test wont test

[squeakyfiji]

So this code will display the news articles when there are articles in the database but it will not print the no current news. If anyone can help me on this that would be great.

<?
//news system

include("./php_include/news_system/news_listing.inc");
$articles = get_news(0);
for ($i = 0; $i < count($articles); $i++){
$counttest = strlen ($articles);
if ( $counttest = 1 )
{
echo "<font> No current news </font>";
} else {
echo "<B>" . $articles[$i]["title"] . "</B><BR><font class='headline'><br></font>" . $articles[$i]["story"] . "<BR>&nbsp;<BR>\n";
}
}

// end of news system
?>

Peace,
Steve

[etully]

Based on the fact that you are referring to count($articles) and you are displaying $articles[$i]['title], it appears that $articles is an array. Therefore, it's meaningless to say: $counttest = strlen ($articles); since strlen is for measuring the length of a string, not an array.

Also (and maybe more importantly), even if you were right that you wanted to check the length of a string, you must use double equal signs like this:

$string_length = strlen ($some_variable);
if ( $string_length == 1 ) { print "The length of the string is 1"; }
else { print "The length of the string is not one"; }

So I guess the main reason that you are never printing "No Current News" is that your if statement is checking the wrong thing. What are you really trying to check?

[squeakyfiji]

I got it - thanks