[RESOLVED] Select Menu + Array Option Values

[obrienkev]

Hi all,

I have a select menu($passed) with an array as an option value.

Using print_r($passed); gives this... pg10003-7049-Yes

I then want to use those 3 separate values.

Below is my foreach loop but it doesnt do anything. The first echo doesn't display anything.

Why is this? Thanks.

foreach($passed as $p => $m)
{
         echo $p .' => '.$m;
	 list($ffnumber, $class_ID) = split('[/.-]', $p);

 foreach($m as $q => $y)
 {
      echo $q .' => '.$y;
      if($y != 'No')
     {
              $query = "UPDATE training ".
		 	     "SET passed = 'Yes' ".
			     "WHERE ffnumber = '$ffnumber' ".
			     "AND class_ID = '$class_ID'";
                $result = mssql_query($query) or die('Update Query Error');
         } // end if
 } // end foreach

} // end foreach

[obrienkev]

Sorry hadnt set the select menu as an array...

<select name="passed[]" id="passed" class="results">

foreach($passed as $p => $m)
{
     //echo $p .' => '.$m;
       list($ffnumber, $class_ID, $pass) = split('[/.-]', $m);

   if($pass != 'No')
      {
       $query = "UPDATE training ".
                       "SET passed = 'Yes' ".
                            "WHERE ffnumber = '$ffnumber' ".
                               "AND class_ID = '$class_ID'";
     echo $query.'<br />';
   //$result = mssql_query($query) or die('Update Query Error');
 } // end if

} // end foreach