[RESOLVED] preg_replace syntax

[sssphp]

How do I replace all '<br />' in a string with '\n' ?

I tried this:

$string = preg_replace( '<br\s/>' , '\n' , $string);

but it gives '<\n>' for each instance.

(If it's not obvious, I'm trying to re-format an HTML string for email, so that line breaks work.)

[Installer]

You need to enclose escaped characters in double quotes: "\n". Try

$string = str_replace('<br />', "\n", $string;

[sssphp]

lol...that took care of the \n, but I still get this in my emails for each instance:

<

The function isn't replacing the opening & closing brackets in '<br />'.

[Installer]

I am unable to replicate that behavior.

BTW, I take it you corrected my typo (closing parenthesis for "str_replace").

[NogDog]

In your original code:

$string = preg_replace( '<br\s/>' , '\n' , $string);

...preg_replace is considering the < and > to be the regex delimiters. Try this:

$string = preg_replace('/<br\s*\/?>/i', "\n", $string);

I tweaked things a bit to match all possible formats, including <br>, <br/>, <BR />, etc.

[sssphp]

Thanks, guys.

Sorry, Installer -- I didn't realize you had changed my preg_replace to str_replace until you mentioned it. Now it works. I'll use that vs. preg_replace since I don't need the regex.