array_intersect

[_salo]

i can't understand why this does't work

$j = 1;
		while (isset($u[$j - 1]))
		{
			$spus = array_intersect($spus, $spusok["$j"]);     //line 88
			$j++;
		}

The text of error is next:
Warning: array_intersect(): Argument #2 is not an array in d:\webserwer\localhost\www\galexpo\vid\visitors_katalog.php on line 88

but $spus and $spusok["$j"] is array (checked).
Help plise.

[NogDog]

Is each element of $spusok an array? (If any one element of $spusok is instead a scalar value, at that point in the loop it will throw that error.)

[Weedpacket]

Is $spusok[$j] guaranteed to exist whenever $u[$j-1] exists?

[_salo]

Weedpacket wrote:

Is $spusok[$j] guaranteed to exist whenever $u[$j-1] exists?

yes

[_salo]

NogDog wrote:

Is each element of $spusok an array? (If any one element of $spusok is instead a scalar value, at that point in the loop it will throw that error.)

print_r($spusok);

Result:
Array ( [0] => Array ( [168] => 170 [169] => 171 ) [1] => Array ( [168] => 170 [169] => 171 ) [2] => Array ( [168] => 170 [169] => 171 ) )

I think a mistake is not here

[Installer]

So $u has only two elements, $u[0] and $u[1]?

Does the error message show for each iteration of the loop, for some iterations, or only once?

[_salo]

Installer wrote:

So $u has only two elements, $u[0] and $u[1]?

Does the error message show for each iteration of the loop, or only once?

$u has three elements $u[0], $u[1] and $u[2], but the error message show only once.

[Installer]

That would be when $j reaches 3. Then $u[$j-1] exists, but $spusok[$j] doesn't (in contradiction of your reply to Weedpacket's question).

[_salo]

Дякую тобі дуже. Таку просту річ сам не зміг зрозуміти, ганьба.
Thanks. Really, now it must work. Thanks again :p