[RESOLVED] opendir how to not show current directory . and ..

iBuddy

Instead of posting on my previous post Im going to make another one on another question I have.

When I run this scrip tit works great BUT it shows (current directory) "." and one level above directory ". ." how do I not show these when running this script?

<html>
<head>
    <title>Browse</title>
    </head>
    <body>
    <h1>Browsing</h1>
    <?
    $current_url = "http://www.domain.com/pics/thumb/";
    $current_dir = "/home/account/public_html/pics/thumb/";
    $dir = opendir($current_dir);
    $i = 0;

while ($file = readdir($dir))


{
$i++;
$newFile = preg_replace("/tn_/i",'',$file);
echo "<a href=http://www.domain.com/pics/$newFile><img src=$current_url$file /></a>";
echo "<br>$file<br>";
}

echo "TOTAL FILES: $i";
echo "<hr><br>";
closedir($dir);
?>
</body>
</html>

Should I do something like this?

		

if (is_dir($file) == "true") { 
#do nothing leave blank
}else{
#continue code
}

Or would there be a better way of doing this

olaf

check how this function is working (the function is collecting only real files)

function select_files($dir) {
    if (is_dir($dir)) {
        if ($handle = opendir($dir)) {
            $files = array();
            while (false !== ($file = readdir($handle))) {
                if (is_file($dir.$file) && $file != basename($_SERVER['PHP_SELF'])) $files[] = $file;
            }
            closedir($handle);
            if (is_array($files)) sort($files);
            return $files;
        }
    }
}

NogDog

If you don't want to show any directories:

if(!is_dir($file))
{
  // do your thing
}

If you don't want to show the current or parent directory but do want to show other directories, then:

if($file != '.' and $file != '..')
{
  // do your thing
}