[RESOLVED] Binary comparison, how?

Hotkey

Hi all!

I've just a short question. As im using some binary comparison in order to check which part of my homepage is visible for the user i want to compare two values against each other.

Short example:
I've got the following visible levels:

Guest = 2 = 001 Binary
Registered = 4 = 010 Binary
Admin = 8 = 100 Binary.

Now when i want an Element of the homepage to be visible only for Registered users and admins i will assign the value 12 (which is 110 Binary).
When it comes to the visible desission i thought i can do the following operation:

$visibleTo = 12; //Element should be visible to Admin and registered user
$currentUserVisibleLevel = 8; //user is admin
$elementIsVisible=($visibleTo & $currentUserVisibleLevel) > 0;
//expected:
//$elementIsVisible = 8 or at least greater then 0
//because 12 & 8 == 110 & 100 = 100 = 8 
echo "result:".$elementIsVisible."!"; //prints result:!

What am i doing wrong??

Thanks in advance and Greets

Hotkey

Solved allready.

The values which i was comparing are stored in variables. Now i've added (int) prior the variables and tadaaaa it's working now.
Anyway, thanks for reading ;-)

how can i mark this thread as "resolved"?

Ascendancy

How long does it take to learn Binary code well? I am guessing it's really confusing.

madwormer2

Just count to four using binary on one hand.

Trust me, it'll help.

Ascendancy

Double the number each time?

Weedpacket

Hotkey wrote:
how can i mark this thread as "resolved"?

It's under "Thread Tools".

Ascendancy wrote:
Double the number each time?

In decimal, 9+3 = 2 and carry the one.

In binary there are only two digits instead of ten, so you have to "carry the one" a lot more often. That's it.