[RESOLVED] Carry a variable over???

[gszauer]

<?php
if($HTTP_GET_VARS["action"]=="addSong"){
?>
<form method="POST" action="index.php?action=addSong1">
<table width="337" border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td>&nbsp;</td>
    <td>Log in to add songs </td>
  </tr>
  <tr>
    <td width="134">Username - </td>
    <td width="203"><label>
      <input type="text" name="username" />
    </label></td>
  </tr>
  <tr>
    <td>Password - </td>
    <td><input type="password" name="password" /></td>
  </tr>
  <tr>
    <td>&nbsp;</td>
    <td><label>
      <div align="right">
        <input type="submit" name="Log in" value="Submit" />
        </div>
    </label></td>
  </tr>
</table>
</form>
<?php
}
if($HTTP_GET_VARS["action"]=="addSong1"){
$username = $_POST["username"];
$password = $_POST["password"];

$result = MYSQL_QUERY("SELECT * from $userTable WHERE username='$username'and password='$password'")
   or die ("Name and password not found or not matched");

$worked = mysql_fetch_array($result);

$username = $worked[username];
//$username  = $worked[username];
//$password = $worked[password];

if($worked){
   echo "Login sucessfull"; 
   ?>
   <form method="POST" action="index.php?action=addSong2">
   <?php
   $username = $_POST["username"];
   ?>
    <input type="submit" name="Submit" value="Continue" />
   </form>
   <?php
   }


}
if($HTTP_GET_VARS["action"]=="addSong2"){
?>
<form method="POST" action="index.php?action=addSong3">
<?php
$username = $_POST["username"];
?>
<table width="296" border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td width="126">&nbsp;</td>
    <td width="170">Add A Song </td>
  </tr>
  <tr>
    <td>Song Title </td>
    <td><label>
      <input name="songName" type="text" id="songName" />
    </label></td>
  </tr>
  <tr>
    <td>Song URL </td>
    <td><input name="songUrl" type="text" id="songUrl" /></td>
  </tr>
  <tr>
    <td>Allow Download? </td>
    <td><label>
      <select name="allowDownload" id="allowDownload">
        <option value="0">Yes</option>
        <option value="1">No</option>
      </select>
    </label></td>
  </tr>
  <tr>
    <td>Download URL </td>
    <td><input name="downloadUrl" type="text" id="downloadUrl" /></td>
  </tr>
  <tr>
    <td colspan="2">** Note to self - commentUrl ** </td>
  </tr>
  <tr>
    <td colspan="2">** Note to self - addUrl ** </td>
  </tr>
  <tr>
    <td colspan="2">** Note to self - plays ** </td>
  </tr>
  <tr>
    <td>&nbsp;</td>
    <td><label>
      <div align="right">
        <input type="submit" name="Submit" value="Submit" />
        </div>
    </label></td>
  </tr>
</table>
</form>
<?php
}

if($HTTP_GET_VARS["action"]=="addSong3"){
$username = $_POST["username"];
$songName = $_POST["songName"];
$songUrl= $_POST["songUrl"];
$allowDownload = $_POST["allowDownload"];
$downloadUrl = $_POST["downloadUrl"];
$commentUrl = "http://programmer2.net";
$addUrl = "http://programmer2.net";
$plays = "7";
$insert = "INSERT INTO $tableName  (artistName,songName,allowDownload,downloadUrl,songUrl,commentUrl,addUrl,plays) 
    VALUES ('".$username."','".$songName."','".$allowDownload."','".$downloadUrl."','".$songUrl."','".$commentUrl."','".$addUrl."','".$plays."')";
mysql_query($insert) or die ("Could not enter information <br>" . mysql_error());
mysql_close();
print ("Song has ben added sucessfully");
}

if($HTTP_GET_VARS["action"]=="cancel"){
}
?>

The code its self works, but i somehow need to carry $username all the way to the last step....
Can anyone help me please?
Thank you
I appriciate your time
~Gabor

[bpat1434]

The code its self works, but i somehow need to carry $username all the way to the last step....

Add it like the rest? $username = $_POST['username'];

[gszauer]

I narrowed it down,
This part of the code won't pass it on, it recives the variable, but refuses to pass it on.

if($HTTP_GET_VARS["action"]=="addSong1"){ 
$username = $_POST["username"]; 
$password = $_POST["password"]; 

$result = MYSQL_QUERY("SELECT * from $userTable WHERE username='$username'and password='$password'") 
   or die ("Name and password not found or not matched"); 

$worked = mysql_fetch_array($result); 

$username = $worked[username]; 
//$username  = $worked[username]; 
//$password = $worked[password]; 

if($worked){ 
   echo "Login sucessfull"; 
   ?> 
   <form method="POST" action="index.php?action=addSong2"> 
   <?php 
   $username = $_POST["username"]; 
   ?> 
    <input type="submit" name="Submit" value="Continue" /> 
   </form> 
   <?php 
   } 


} 

[bpat1434]

it doesn't pass it on because there's nothing being passed in the form 😉 You have to pass hidden fields in the form in order for info to be passed on w/o user knowledge. Just assigning a value to $username doesn't make a hidden input field in the HTML.

[gszauer]

Ah, makes sence...
i thought i coud just pass it as a variable... Thanks