using a variable inside of an EXEC() statement

[Tizza]

Hi all

I am running into an issue...

exec('schtasks /CREATE /ST 15:00 /TN $id /TR c:\second.php /SC once /RU "NT AUTHORITY\SYSTEM"');

above is the command i am trying to execute within a php script, and $id is a variable that is passed through another program. $id is represented by a 5 digit number.

What i am trying to do is create a task once my script runs that has the $id number as the task name.

each time i run the above, my task is named $id and not the number that the variable represents.

Any ideas?

Thanks!!

[ClarkF1]

It might be because of the single quotes. Try swapping the single and double quotes round.

[Tizza]

if i do that the script just hangs. If you do schtasks /create /? from the command prompt, it says that the /RU needs the username wrapped in double quotes.

I have tried removing the single quotes, and repalcing with double quotes, adding both double and single quotes, wrapping /TN $id in single and double quotes... ive tried everything!

There must be a way of doing htis... otherwise you could never schedule multiple tasks using 1 schtask command. if the AT scheduler encounters an existing task taht is scheduled, it renames the identifier itself by incrementing by 1. but if schtasks task encounters an existing task, it fails because it already exists due to the unique taskname denoted by /TN. the $id i am using is unique each time the script runs which is why i want the taskname to be named this variable.

any help is greatly appreciated!!!!!!!!

Thanks

[madwormer2]

exec('schtasks /CREATE /ST 15:00 /TN '.$id.' /TR c:\second.php /SC once /RU "NT AUTHORITY\SYSTEM"');