How do I display the <select> <option> that was chosen?

[dai_hop]

Hi everyone,

I have a select with three options, when I submit the form with $_SERVER['PHP_SELF'] I want the select to display the option that was chosen.

Can anyone help me out with this please? 🙂

Cheers,

dai.hop

[Azala]

Just check the submitted value against the value of the options.

for example:

$mySelect = "<select name=\"mySelect\">";
for ($x=0;$x<3;$x++){
$selected = (isset($_POST["mySelect"]) && $_POST["mySelect"] == $x) ? "selected=\"selected\"" : "";
$mySelect .= "<option value=\"".$x."\" ".$selected.">sometext</option>";
}
$mySelect .= "</select>";
echo $mySelect;

[cahva]

This should do it..

$foo = isset($_POST['foo']) ? $_POST['foo'] : '';
$options = array('One'=>1, 'Two'=>2, 'Three'=>3);

echo '<select name="foo">';
foreach ($options as $k=>$v) {
	$sel = ($foo == $v ? ' selected="selected"' : '');
	echo '<option value="'.$v.'"'.$sel.'>'.$k.'</option>';
}
echo '</select>';

If you are wondering about those $foo and $sel, you can do them in traditional way with if .. else .. like:

if (isset($_POST['foo'])) $foo = $_POST['foo']; else $foo = '';

EDIT: too slow 🙂