[RESOLVED] Array Question - $rand_array and Saving Results as a Variable

[yorktown]

I have an array and want to use the results from a loop as a variable.

Example:

$array = array ( '1' , '2' , '3' , '4' , '5' , '6' , '7' , '8' );

srand (time());

$key1=rand(2,5); // Chooses a number between 2 and 5

$randresult = array_rand($array,$key1);

$i=0;
while ($i < $key1) {
echo $array[$randresult[$i]] ."<br> \n"; // ******MY PROBLEM IS HERE
$i++; }

What I really want are the 2 to 5 results of the array stored as a variable so I can use them elsewhere.

Only the following command works---> echo $array[$randresult[$i]] ."<br> \n";
(That prints it on the screen and doesn't create a variable for it)

when I try:

  $savedvariable= "$array[$randresult[$i]] .<br> \n";
   (I tried this with and without the period(.))

I get a syntax error.

I get nothing when I try this as well:

   $savedvariable= "$array($randresult[$i]) .<br> \n";
   (I tried this with and without the period(.))

How do I save the result of the random array as a variable?

[ClarkF1]

$output = "";
while ($i < $key1) {
$output .= $array[$randresult[$i]] ."<br> \n";
$i++; }

$output contains the string.

If you want them stored in an array use:

$output = array();
while ($i < $key1) {
$output[] = $array[$randresult[$i]];
$i++; }