[RESOLVED] Getting value "array"

[MitchEvans]

My output of a text box is giving the answers "array"

Here is the textbox:

<TEXTAREA NAME='text{$productRow1['id']}[]' ROWS=3 COLS=60>
</TEXTAREA>

An here is the code for output on the next page:

for ($i=0; $i<$num; $i++) { 
   // Fetch data from survey table here 
   $rows= mysql_fetch_array ($results); 

   $s='';
   $t=''; 
   $u=''; 

   $array_name= 'myradio'.$rows['id']; 
  $array_name1='text'.$rows['id'];
 if (isset($_POST[$array_name])) { 
      foreach ($_POST[$array_name] as $key => $val) { 
        if ($val=='yes') $s='Yes' AND $t=$_POST[$array_name1]; 
        else if ($val=='no') $s='No' AND $t=$_POST[$array_name1]; 


				$currentPlace = count($line);				
				$line[$currentPlace][0] = $rows['requirement_txt'];
				$line[$currentPlace][1] = $s;
				$line[$currentPlace][2] = $t;
				//$line[$currentPlace][3] = $u;
				$line[$currentPlace][4] = "Module 1";
}}}

Any ideas how I can get $t to output the actual results of the textbox (whatever is typed in the textbox)
Any helps is great thanks!!!

[MitchEvans]

I've sorted it with the following code, works a treat! Thought it would be a lot more complicated!

 $array_name= 'myradio'.$rows['id']; 
$array_name1='text'.$rows['id'];
 if (isset($_POST[$array_name])) { 
	 if (isset($_POST[$array_name1])) {
		 foreach ($_POST[$array_name1] as $key1 => $val1) {
      foreach ($_POST[$array_name] as $key => $val) { 
        if ($val=='yes') $s='Yes' AND $t=$val1; 
        else if ($val=='no') $s='No' AND $t=$val1;