using the mysql_fetch_array and displaying data

[terrypeck36]

$string3 = "SELECT id, name FROM table WHERE name LIKE '%$name%'";
$resultID = mysql_query($string3);

    $numrow = mysql_num_rows($resultID);


while($row=mysql_fetch_array($resultID)){

	//print_r($row);

	$id = $row['id'];
	$name = $row['name'];

I have this query where i am trying trying to return print multiple rows but it only displays the last row of data. if i print_r the array it returns and displays two arrays

array([0]=>1 [id]=>1 [1]=> timmy [name]=>timmy) array([0]=>2[id]=>2......billy..

i want to print 1 timmy and 1 billy but all i get is the last record 1 billy

[NogDog]

Just place your print or echo commands within the while loop:

echo "<ul>\n";
while($row = mysql_fetch_assoc($resultID))
{
  echo "<p>{$row['id']} {$row['name']}</ul>\n";
}
echo "</ul>\n";