sizeof()?

[lukeurtnowski]

I think something is wrong but I can't figure out what
I'n this code

$Img1 = $result["Image1"];
$Image1 = $imgdir.$Img1; }

$Img2 = $result["Image2"];
$Image2 = $imgdir.$Img2;

$Img3 = $result["Image3"];
$Image3 = $imgdir.$Img3;

$Img4 = $result["Image4"];
$Image4 = $imgdir.$Img4;

$Img5 = $result["Image5"];
$Image5 = $imgdir.$Img5;

$Img6 = $result["Image6"];
$Image6 = $imgdir.$Img6;
...
$Photos = array(1 => $Img1, $Img2, $Img3, $Img4, $Img5, $Img6);
$sizeOfPhotos = sizeof($Photos);
echo $sizeOfPhotos;

I have something in $result["Image1"], $result["Image4"], and in $result["Image6"] but I get 6 returned, shouldn't it be 3?
Thanks

[NogDog]

You've assigned six values to array $Photos, so sizeof() is returning 6. (It doesn't care if some of the elements' values are null, 0, FALSE, or an empty string: the array elements have still been populated.)

[bretticus]

lukeurtnowski wrote:

I think something is wrong but I can't figure out what
I'n this code....I have something in $result["Image1"], $result["Image4"], and in $result["Image6"] but I get 6 returned, shouldn't it be 3?
Thanks

All I see is you setting an array with six elements and sizeof correctly telling you there's six elements...

$Photos = array(1 => $Img1, $Img2, $Img3, $Img4, $Img5, $Img6);
$sizeOfPhotos = sizeof($Photos);
echo $sizeOfPhotos;

[bretticus]

NogDog, you win again 😉 (you do notice the same time on our posts, right?) 😃

[NogDog]

bretticus wrote:

NogDog, you win again 😉 (you do notice the same time on our posts, right?) 😃

That's because I have the power of Hex at my disposal. 😉

[lukeurtnowski]

ok, then how do I count only the ones that are not null?
Thanks

[bretticus]

foreach ($Photos as $Photo) {
	if ( !is_null($Photo) )
		$sizeOfPhotos++;
}

is one way.

[lukeurtnowski]

still returns 6

$Photos = array(1 => $Img1, $Img2, $Img3, $Img4, $Img5, $Img6);
foreach ($Photos as $Photo) {
    if ( !is_null($Photo) )
        $sizeOfPhotos++;
} 
echo $sizeOfPhotos;

[Weedpacket]

Or use [man]array_filter[/man] and count what's left.

But really; using variables (like $result['Image4']) that don't have values is just nasty. You shouldn't be doing it in the first place (and PHP would be complaining about it if Notice-level error messages hadn't been turned off).

[bretticus]

lukeurtnowski wrote:

still returns 6

$Photos = array(1 => $Img1, $Img2, $Img3, $Img4, $Img5, $Img6);
foreach ($Photos as $Photo) {
    if ( !is_null($Photo) )
        $sizeOfPhotos++;
} 
echo $sizeOfPhotos;

Well, I must admit, my answer was meant more illustrative than literal. I never bothered to look at how your variables were being set nor what they were being set to as the mystery of 6 was so apparent at first glance. How could anyone here know exactly what type of variable was in the $result array anyways?

Since the variables are probably not nulls literally, is_null will never be true even on empty strings (which, in fact, are not null.) So, being a bit more literal this time around, you might trying substituting empty() for is_null() as empty() pretty much spans the whole range of the definition of "empty variable." I trust you'll spend a little time with the manual if an unexpected result surfaces again.

[lukeurtnowski]

ok, thanks...