Displaying the current week

anthill

I found this code in one of the phpbuilder forums (http://www.phpbuilder.com/board/showthread.php?t=10222903&page=1&pp=15) but can't get my head around why the week is displaying as next week and not the current week!

Th code i'm using is:


<? 
function WeekToDate ($week, $year)
{
$Jan1 = mktime (1, 1, 1, 1, 1, $year);
$iYearFirstWeekNum = (int) strftime("%W",mktime (1, 1, 1, 1, 1, $year));

if ($iYearFirstWeekNum == 1)
{
$week = $week - 1;
}

$weekdayJan1 = date ('w', $Jan1);
$FirstMonday = strtotime(((4-$weekdayJan1)%7-3) . ' days', $Jan1);
$CurrentMondayTS = strtotime(($week) . ' weeks', $FirstMonday);
return ($CurrentMondayTS);
}

$iWeekNum = strftime("%U");
$iYear = date("Y");

$sStartTS = WeekToDate ($iWeekNum, $iYear);
echo $sStartDate = date ("F d, Y", $sStartTS)."<br>";
echo $sEndDate = date ("F d, Y", $sStartTS + (6*24*60*60));


?>

Is this something to do with the fact the first day of 2006 was a Sunday? I've tried using %U and %u but it sitll won't give me the current week. I could always do -1 on the weeknum but think this will give me complications next year.

Any ideas?

Thanks

Ant

Installer

It will work if you change this line:

$iYearFirstWeekNum = (int) strftime("%W",mktime (1, 1, 1, 1, 1, $year));

to:

$iYearFirstWeekNum = (int) strftime("%W",mktime (1, 1, 1, 1, 4, $year));

(It works for this year, anyway.)

anthill

Thanks! thats spot on. But why changing the mktime day value to 4?

Ant

Installer

Because the 4th is always in week #1, and the 1st often isn't, like this year.