function formatDate($datestr = '', $format = 'd M Y G:i')
{
if ($datestr == '')
{
return FALSE;
}
$datestr = trim($datestr);
$datestr = preg_replace("/\040+/", "\040", $datestr);
if ( ! ereg("^[0-9]{2,4}\-[0-9]{1,2}\-[0-9]{1,2}\040[0-9]{1,2}:[0-9]{1,2}.*$", $datestr))
{
return FALSE;
}
$split = preg_split("/\040/", $datestr);
$ex = explode("-", $split['0']);
$year = (strlen($ex['0']) == 2) ? '20'.$ex['0'] : $ex['0'];
$month = (strlen($ex['1']) == 1) ? '0'.$ex['1'] : $ex['1'];
$day = (strlen($ex['2']) == 1) ? '0'.$ex['2'] : $ex['2'];
$ex = explode(":", $split['1']);
$hour = (strlen($ex['0']) == 1) ? '0'.$ex['0'] : $ex['0'];
$min = (strlen($ex['1']) == 1) ? '0'.$ex['1'] : $ex['1'];
if (isset($ex['2']) AND ereg("[0-9]{1,2}", $ex['2']))
{
$sec = (strlen($ex['2']) == 1) ? '0'.$ex['2'] : $ex['2'];
}
else
{
// Unless specified, seconds get set to zero.
$sec = '00';
}
if (isset($split['2']))
{
$ampm = strtolower($split['2']);
if (substr($ampm, 0, 1) == 'p' AND $hour < 12)
$hour = $hour + 12;
if (substr($ampm, 0, 1) == 'a' AND $hour == 12)
$hour = '00';
if (strlen($hour) == 1)
$hour = '0'.$hour;
}
return date($format,mktime($hour, $min, $sec, $month, $day, $year));
}
I have this function that I was given by a friend, I modified slightly (cant remember how much... i got it about a year ago). Anyway...
As the title of the subject suggests its to change a mySQL datetime string into a Unix timestamp so it can be used in the PHP date() function.
I was thinking it seemed like a very long winded way of doing it. Is there a better, neater, shorter solution?
Thanks