$today = date("m d y");
$month = date("m");
$day = date("d");
$year = date("y");
// --
$query = @mysql_query("SELECT * FROM $table");
$total_rows = @mysql_num_rows($query);
$counter = 0;
while($ourData = @mysql_fetch_array($query)){
$adUrl = $ourData["adUrl"];
$adName = $ourData["adName"];
$exMonth = $ourData["exMonth"];
$exDay = $ourData["exDay"];
$exYear = $ourData["exYear"];
$impressions = $ourData["impressions"];
$adAt
$counter++;
print ("&adUrl$counter=$adUrl");
}
My basic code is above,
I would like to know how i could make
print ("&adUrl$counter=$adUrl");
only print IF the ad is not expired, so i put
$month = date("m");
$day = date("d");
$year = date("y");
//...
$exMonth = $ourData["exMonth"];
$exDay = $ourData["exDay"];
$exYear = $ourData["exYear"];
I am a n00b at php, and have no clue how to write an appropriate if statement, so if the ad has expired it wont play....
Can anyone PLEASE help me out?
I really appritiate your time.
~Gabor Szauer