[RESOLVED] when $x ='01'; $x++: Returns '2' NOT '02'???

[fuzzy1]

Hey All,
The Following will return '2006-2-Joe' when I need '2006-02-Joe'

//for context,  $curName would be something like 2006-01-Joe through 2006-13-Joe 
//where '01 & 13 are NOT DATES.
//$userString = substr($curName, -8);
//$periodString = substr($curName, 5, 2);
// so for arguement sake say that...
	$Y = date('Y');
	$periodString='01';
	$userString='Joe';
	$time_to_update_template = $today;
if ($time_to_update_template = $today){
	$periodString+=1;
	$newTemplate = "$Y.'-'.$periodString.'-'.$userString";
}
// which will return '2006-2-Joe' and not '2006-02-Joe'

Please,

1. How do I fix it so I get 01-09?

2. How do I set it so that it starts over after 13 (or on the new year)?
   cause I can't seem make this...

   $period=1;
   while($i<=13)
     {
     $period++;
     }

   ...work for me in this context:eek:

[NogDog]

I'd probably use sprintf() to format it.

$newTemplate = sprintf('%04d-%02d-%s', $Y, $periodString, $userString);

[fuzzy1]

Short and sweet!
Geezz NogDog! Do you ever sleep?
Many Thanks!

if ($periodString <= 12){
	$periodString+=1;
}else{$periodString=1;}
$newTemplate = sprintf('%04d-%02d-%s', $Y, $periodString, $userString);