html code in echo

[nelsonbarroca]

hey

i try to put this working but in some point it incorrect, i try 2 different ways, the code is:

<td>
<?php echo "<input type=\"button\" name=\"refererEditBtn\" value=\"Edit\" class=\"form\" onClick=\"frmAllowedReferers.refererBtnIDName.value='".$line."'; frmAllowedReferers.refererBtnValue.value='Edit'; frmAllowedReferers.submit();\">"; ?> 
</td>

or

<td>
<?php echo "<input type='button' name='refererEditBtn' value='Edit' class='form' onClick='frmAllowedReferers.refererBtnIDName.value='".$line."'; frmAllowedReferers.refererBtnValue.value='Edit'; frmAllowedReferers.submit();'>"; ?> 

</td>

thanks for any help,

Nelson

[nelsonbarroca]

simple example:

<td>
<?php echo "<input type=\"button\" name=\"refererEditBtn\" value=\"Edit\" class=\"form\" onClick=\"frmAllowedReferers.refererBtnIDName.value='".$line."'; >"; ?> 
</td>

thanks,

Nelson

[ClarkF1]

What exactly is the problem? Do you get an error message.

Have you tried

<td>
<input type="button" name="refererEditBtn" value="Edit" class="form" onClick="frmAllowedReferers.refererBtnIDName.value="<?php echo $line; ?>">
</td> 

[nelsonbarroca]

well i try it again... but no success, this is the all input:

<input type="button" name="refererEditBtn" value="Edit" class="form" onClick="frmAllowedReferers.refererBtnIDName.value="<?php echo $line; ?>"; frmAllowedReferers.refererBtnValue.value="Edit"; frmAllowedReferers.submit();">

_

thnks alot ClarkF1

[ClarkF1]

This should work:

<input type="button" name="refererEditBtn" value="Edit" class="form" onClick="frmAllowedReferers.refererBtnIDName.value='<?php echo $line; ?>'; frmAllowedReferers.refererBtnValue.value='Edit'; frmAllowedReferers.submit();">

There were double quotes where there should have been single quotes

[nelsonbarroca]

it don't work...

give me the error in browser:
unterminated string lateral

:queasy:

[nelsonbarroca]

i try change echo to print but same error...

refererBtnIDName.value='<?php echo $line; ?>';

to:

refererBtnIDName.value='<?php print($line); ?>';

_

[ClarkF1]

It works for me..........

Are you sure the error is related to that or something else on the page.

If you have a ' or " in the value of $line make sure you use

echo addslashes($line);

instead of just

echo $line;

[nelsonbarroca]

i found one of the problem
with trim function it send correctly the first part, but after don't send correctly the second part:

frmAllowedReferers.refererBtnValue.value='Edit';

of

<input type="button" name="refererEditBtn" value="Edit" class="form" onClick="frmAllowedReferers.refererBtnIDName.value='<?php echo trim($line); ?>'; frmAllowedReferers.refererBtnValue.value='Edit'; frmAllowedReferers.submit();">
_

thanks for any help