Usage of ? in echo

firstlast0

for($i = 1; $i <= $total_pages; $i++) { if($i == $page_number) { print "$i "; } 
else { print "<a href="lists.php?page_number=$i">"$i"</a>"; } }

Hi, I try to implement a basic pagination system to view my table outputs divided into the pages. I sort out and write a code with my near to the zero knowledge however i'm stuck with a simple problem while creating the pagination links with a for loop and echo.

I used the above code to generate the links however the links generated by that code looks like this:

http://lists.php/?page_number=2

As it can be seen easily between "lists.php" and "?" a "/" automatically put by the code which breaks the link itself.

I'm sure this is a pretty easy to solve problem, but dont forget that i'm a newbie 🙂

I really appreciate for a solution, thx in advance : )

laserlight

You forgot to escape the double quotes in the double quote delimited strings.

firstlast0

Hi laserlight,

I don't get it... With the above code i can generate the tables and links without any error except the extra added "/" part.

Can you show me on my code where should i close it ?

Thx

laserlight

I don't get it... With the above code i can generate the tables and links without any error except the extra added "/" part.

The code example that you provided will result in a parse error.

firstlast0

laserlight wrote:
The code example that you provided will result in a parse error.

No it doesn't give any parse error; actually except the part i asked it works very well. I can get the tabular data as i want without any error, also pagination works well.

laserlight

No it doesn't give any parse error; actually except the part i asked it works very well.

hmm... did you rewrite your code when you posted? I suggest that you copy and paste the code that you are actually using. If you look at the code highlighting provided by this messageboard system, it is easy to see that the code that you posted has a syntax error.

firstlast0

Here's my code:

...

for($i = 1; $i <= $total_pages; $i++) { if($i == $page_number) { print "$i "; } 
else { echo "<a href=\"http://test2.php?page_number=".$i."\" >".$i."</a>"; }};

...

?>
</HTML>

stolzyboy

you have http://msidene2.php?page_number in there... do you not want the url/ip in there?

that could be your issue

laserlight

I think the problem is that "http://msidene2.php?page_number=" is not the URL that you want. Basically, it is interpreted as a URI with a domain name "msidene2.php". If you remove the protocol portion "http://", or fully qualify with your actual domain name (which may be less flexible), the problem should be solved.

firstlast0

laserlight wrote:
I think the problem is that "http://msidene2.php?page_number=" is not the URL that you want. Basically, it is interpreted as a URI with a domain name "msidene2.php". If you remove the protocol portion "http://", or fully qualify with your actual domain name (which may be less flexible), the problem should be solved.

That's it ! Removing "http://" portion of the code fixed my problem.

Thanks a lot 🙂

bradgrafelman

Don't forget to mark this thread resolved.