[RESOLVED] 2 second code review...

chrisj8221

that is if you know what you are doing. I'm trying to figure out php and need help... again.

I want to have an include statement where the $url is pulled from the following

following is the code I am trying to use, but it's not working, where is the comma, semi c, or whatever I am missing. have been working on this for about 20 minutes and figure someone who knows what they are doing can let me know in about 2 seconds...

<?php include('echo "$url" /review/header.php'); ?>

thanks in advance.

chris

Kudose

<?php
  $url = 'http://www.domain.com';  

  echo file_get_contents($url.'/index.php'); 

  /** or **/
  include $url.'/index.php';
?>

NogDog

<?php include $url.'/review/header.php'; ?>

NogDog

PS: Note that if you include a file from a URL, any PHP in it will most likely be processed on that server, and all that will actually be included in your calling script is any HTTP output from that included file.

chrisj8221

yep 2 seconds...

thanks

chris

bradgrafelman

Why are you using [man]include/man across HTTP? If you're just trying to display the HTML of another site, something like [man]readfile/man would better suit the job (so that PHP doesn't waste time trying to parse the data for PHP code).

chrisj8221

there is a little php code in the file I am including. The above solutions worked so thank you very much everyone for helping out another newbie.

chris

Weedpacket

bradgrafelman wrote:
Why are you using include() across HTTP?

chrisj8221 wrote:
The above solutions worked

Getting from New York City to Boston by flying from New York City to San Francisco and then flying from San Francisco to Boston works as well. And makes about as much sense.

Kudose

You two are so freakin smart.

chrisj8221

so am I to gather the best way to pull something in without a lot of php code in is by the

readfile ()

command and not the

file_get_contents()

???

thanks

Weedpacket

If the file you're wanting to read is on the same server, the smart thing is to use its filename and not a URL.

chrisj8221

i tried referencing the file name but the file is included in several directories on the server.

www.domainname.com/
www.domainname.com/review
www.domainname.com/review/admin
etc...

using the readfile('/header.php') ;

only works with the files in the same directory location, or is there some syntax trick i am missing...

chris

bradgrafelman

Script location (via web): http://mydomain.com/foo/bars/are/tasty/myscript.php
Target file (via web): http://mydomain.com/includes/header.php

Relative path to use: ../../../../includes/header.php

Script location (via web): http://mydomain.com/myscript.php
Target file (via web): http://mydomain.com/includes/somewhere/else/header.php
Relative path to use: includes/somewhere/else/header.php

bradgrafelman

Also, if you're wondering where on the server the current script is, try doing this:

echo __FILE__;

Weedpacket

And other information about where files are located (such as the DOCUMENT_ROOT and SCRIPT_PATH) is recorded in the $_SERVER array.

Just keep in mind that URLs are not filenames (which is a good thing; there are nearly 200,000 threads on these forums - each with its own URL or we wouldn't be able to tell them apart - but we only one file to display them: "showthread.php".)