[RESOLVED] Adding PHP Code to Variable

obrienkev

Hi all,

How do I correctly add the php code below to the variable $output? Thanks.


$output = '<div id="header"> '.
		  <?php
			include('../header.htm');
		  ?>
                 '</div> <!-- end Header -->';

ClarkF1

You could use file_get_contents rather than include but you need to be wary of quotation marks within the file and use addslashes.

obrienkev

sorry I meant within the correct syntax. Do I add '' around the php tags? thanks.

bradgrafelman

There is no correct syntax... you can't use [man]include[/man] to concatenate a file's value within a string. [man]file_get_contents/man, however, retrieves the contents of the file and returns it as a string.

ClarkF1

And you won't need the php tags

bradgrafelman

And if header.htm is a static HTML file, there's no reason to use the include/require functions.

obrienkev

I want to contact to a string...

is this on the right track??


$output = '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" '.
                    'http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> '.
                    "\n\n".
                    '<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en"> '.
                    "\n\n".
                    '<head> '.
                    "\n\n".
                    '<title>TA Generic Procedures - '.$title.'</title> '.
                    '<link rel="stylesheet" type="text/css" href="../css/screen.css" /> '.
                    '<script language="JavaScript" src="../menu.js"></script> '.
                    "\n\n".
                    '</head> '.
                    "\n\n".
                    "\n\n".
                    '<body> '.
                    "\n\n".
                    '.<div id="wrapper"> '.
                    "\n\n".
                    '<div id="header">
              <?php
                     include(\'../header.htm\');
                  ?>
                  </div> <!-- end Header --> '.
                  "\n\n".
              '<div id="content"> '.
              "\n\n".
              '<h1>Fundshare</h1>
                <?php
                // load image
                  include('../display_img.php');
                // connect to db
                  include('../db_connect.php');
                  $query = "SELECT $title, last_updated ".
                                    "FROM $table";
                  $result = mssql_query($query) or die('Select Error');
                  //echo 'TR:'.$num_results = mssql_num_rows($result);
                  $row = mssql_fetch_array($result);
                  echo '<p class="edit_date">Last Updated: '.$row['last_updated'].'</p>';
                  echo stripslashes($title);
          ?>
          </div> <!-- end Content --> ';

liquorvicar

What are you trying to achieve? Did you want your $output variable to include the string literal

<?php
                     include(\'../header.htm\');
                  ?>

? Or do you want your variable to include the contents of your header.htm file?

bradgrafelman

As liquorvicar asked, we need some clarification on whether you want this script to output the text "<?php include('header.htm') ?>" or if you actually want to load the header.htm file and output its data.

Also, it might be easier for you to use the HEREDOC syntax:

$output = <<<END_OF_STRING
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN
                    http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en">

<head>
<title>TA Generic Procedures - {$title}</title>

etc.

END_OF_STRING;

wilku

I'm guessing, what you try to achieve is to put what would be normally displayed in browser with include in some varible?
If so then output buffering is what you need:

$output = "whatever at the beginning";

ob_start(); //start output buffering
include('../header.html'); // this isn't sent to the browser, it's buffered instead
$output.=ob_get_contents(); //add what's in the buffer to the varible
ob_end_clean(); //turn off output buffering and clean the buffer (without sending to browser)

$output.="whatever should be next";

obrienkev

yes I want the string to output <?php include('header.htm') ?>

How do I do this? Thanks.

Tried HEREDOC...


<?php

$output = <<<PAGE_CONTENT
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en">

<head>
<title>TA Generic Procedures - Operations Procedures - List of Funds</title>

<link rel="stylesheet" type="text/css" href="../css/screen.css" />

<script language="JavaScript" src="../menu.js"></script>

</head>

<body>

<div id="wrapper">


<div id="header">

	  <?php

		  include('../header.htm');

		?>

	</div> <!-- end Header -->


<div id="content">

	  <h1>List of Funds &amp; Relevant Dealing Cut-Off Points</h1>

		<?php

		  // load image
			include('../display_img.php');

		  // connect to db
			include('../db_connect.php');

			$query = "SELECT list_of_funds, last_updated ".
						 	 "FROM operations_procedures";
			$result = mssql_query($query) or die('Select Error');

			$row = mssql_fetch_array($result);

			echo '<p class="edit_date">'.$row['last_updated'].'</p>';

			echo $row['list_of_funds'];

		?> 


</div> <!-- end Content -->


	<div id="sidecol">

	  <?php
		  include('../menu.htm');
		?>

	</div> <!-- end Side Column -->


</div> <!-- end Wrapper -->

</body>
</html>

PAGE_CONTENT;

wilku

I still don't understand what you try to achieve. But let's say you have

<?php
//header.php
echo "This is the first header line<br>";
echo "This is the second header line<br>";
echo "This is the third header line<br>";
?>

Thera are three possibilities what you can do:

1. echo string only

<?php
$output =  htmlspecialchars("<?php include('header.php');?>");

echo $output;
?>

This will show that $output is

<?php include('header.php');?>

2. echo the content of the file

<?php
$output =  nl2br(htmlspecialchars(file_get_contents('header.php')));

echo $output;
?>

This will show that $output is

<?php
//header.php
echo "This is the first header line<br>";
echo "This is the second header line<br>";
echo "This is the third header line<br>";
?>

3. echo the result of executing header.php

<?php
ob_start();
include('header.php');
$output = ob_get_contents();
ob_end_clean();

echo $output;
?>

This is the first header line<br>
This is the second header line<br>
This is the third header line<br>

There isn't much more you can do with that file and the varible 😉

obrienkev

1/ I have a blank page template and want to make a copy of it as below...

			 $file = 'template.php'; //TEMPLATE
			 $newfile = $title.'.php'; // FILE COPY

		 $filedir = '../'.$folder.'/'.$newfile; // FILE DIRECTORY

		 // COPY OVER FILE TEMPLATE
		 if (!copy($file, $filedir)) {
	       //echo "failed to copy $file...\n";
		 }
		 else
		 {
 		       //echo 'File Created.';
		 }

2/ Then I want to write $output to this new page...

			 // OPEN COPIED FILE
			 $fp = fopen($filedir, "w");

		 fwrite($fp, $output); // WRITE TO FILE

		 fclose($fp); // CLOSE FILE

The new page should contain this code...

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en">

<head>
<title>TA Generic Procedures - Impress Procedures</title>

<link rel="stylesheet" type="text/css" href="../css/screen.css" />

<script language="JavaScript" src="../menu.js"></script>

</head>

<body>

<div id="wrapper">


<div id="header">

	  <?php

		  include('../header.htm');

		?>

	</div> <!-- end Header -->


<div id="content">

	  <h1>Impress Procedures</h1>

		<?php

		  // load image
			include('../display_img.php');

		  // connect to db
			include('../db_connect.php');

			$query = "SELECT impress, last_updated ".
						 	 "FROM impress_procedures";
			$result = mssql_query($query) or die('Select Error');
			//echo 'TR:'.$num_results = mssql_num_rows($result);

			$row = mssql_fetch_array($result);

			echo '<p class="edit_date">Last Updated: '.$row['last_updated'].'</p>';

			echo stripslashes($row['impress']);

		?> 


</div> <!-- end Content -->


	<div id="sidecol">

	  <?php
		  include('../menu.htm');
		?>

	</div> <!-- end Side Column -->


</div> <!-- end Wrapper -->

</body>
</html>

so how do I assign this to $output????

sorry for not clearly explaining it.

wilku

Now I get it. 🙂

HEREDOC is a way to go. Just change all your $ there to \$ so it doesn't treat varibles as varibles.

$output = <<<PAGE_CONTENT
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en">

<head>
<title>TA Generic Procedures - Operations Procedures - List of Funds</title>

<link rel="stylesheet" type="text/css" href="../css/screen.css" />

<script language="JavaScript" src="../menu.js"></script>

</head>

<body>

<div id="wrapper">


<div id="header">

      <?php

          include('../header.htm');

        ?>

    </div> <!-- end Header -->


<div id="content">

      <h1>List of Funds &amp; Relevant Dealing Cut-Off Points</h1>

        <?php

          // load image
            include('../display_img.php');

          // connect to db
            include('../db_connect.php');

            \$query = "SELECT list_of_funds, last_updated ".
                              "FROM operations_procedures";
            \$result = mssql_query(\$query) or die('Select Error');

            \$row = mssql_fetch_array(\$result);

            echo '<p class="edit_date">'.\$row['last_updated'].'</p>';

            echo \$row['list_of_funds'];

        ?>


</div> <!-- end Content -->


    <div id="sidecol">

      <?php
          include('../menu.htm');
        ?>

    </div> <!-- end Side Column -->


</div> <!-- end Wrapper -->

</body>
</html>

PAGE_CONTENT;

obrienkev

thanks!

How do I deal with the semicolon ; here... include('../header.htm');

liquorvicar

Make sure you have no trailing spaces at the end of your heredoc.

PAGE_CONTENT;

When I copied and pasted it there was a space at the end of this line which was causing a problem.

obrienkev

still have same issue. Page is displayed as blank so there must be a syntax error.

<?php

//list($title1, $title2) = split('[/-._]', $title); // SET HEADING


$output = <<<PAGE_CONTENT
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en">

<head>
<title>TA Generic Procedures - Operations Procedures - List of Funds</title>

<link rel="stylesheet" type="text/css" href="../css/screen.css" />

<script language="JavaScript" src="../menu.js"></script>

</head>

<body>

<div id="wrapper">


<div id="header">

      <?php

          include('../header.htm');

        ?>

    </div> <!-- end Header -->


<div id="content">

      <h1>List of Funds &amp; Relevant Dealing Cut-Off Points</h1>

        <?php

          // load image
            include('../display_img.php');

          // connect to db
            include('../db_connect.php');

            $query = "SELECT $title, last_updated ".
                              "FROM $table";
            $result = mssql_query($query) or die('Select Error');

            $row = mssql_fetch_array($result);

            echo '<p class="edit_date">'.$row['last_updated'].'</p>';

            echo $row['list_of_funds'];

        ?>


</div> <!-- end Content -->


    <div id="sidecol">

      <?php
          include('../menu.htm');
        ?>

    </div> <!-- end Side Column -->


</div> <!-- end Wrapper -->

</body>
</html>

PAGE_CONTENT;
?>

Then in the main page the above code is called here...

include('output.php');

Thanks!

liquorvicar

Have you got display_errors and error_reporting turned on? That would tell you if you had a syntax error.

Otherwise, are you actually echo-ing the $output variable somewhere?

obrienkev

Get this error now...

Parse error: parse error, expecting T_STRING' orT_VARIABLE' or `T_NUM_STRING' in C:\Inetpub\wwwroot\transfer_agency\new_page\output.php on line 55

What does this mean?

I set display_errors = On in my php.ini file

liquorvicar

Don't forget you need to escape your variables with a backslash, i.e. "\$variable" rather than "$variable".