dynamic content and html frames

sander_ESP

hello,

i have a page called hallfame.html it consists of two frames.

in the left one, pictures are loaded of the hall of fame members. in the right one the hall of fame general page is loaded.

what i want to to is when people click on one of the pictures in the left frame, their detail come up in the right frame..

every hall of fame member has a unique person_ID. this is used to load the right info for the user in the detail page.

sp far so good.. the problem i have is when i click on a picture, the left frame gets refreshed instead of the right one.

following code is used to make display the images in the left frame and make them clickable

$i=0;
$str='';
if (mysql_num_rows($numberresult)>0)
{
while ($row = mysql_fetch_array($numberresult, MYSQL_ASSOC))
{
$i++;
//$str .= $i.". ";
$str .= "<a href=\"welcome.php?act=view&iid=".$i."\">";
$str .= "<img border=\"0\" height=\"127\" width=\"100\" src=\"image1.php?act=view&iid=".$i."\"></a> ";

}
print $str;
}

now i know i have to set a target= mainframe somewhere. i tried adding it in the code above, making it look like this

$i=0;
$str='';
if (mysql_num_rows($numberresult)>0)
{
while ($row = mysql_fetch_array($numberresult, MYSQL_ASSOC))
{
$i++;
//$str .= $i.". ";
$str .= "<a href=\"welcome.php?act=view&iid=".$i."\"target="mainFrame">";
$str .= "<img border=\"0\" height=\"127\" width=\"100\" src=\"image1.php?act=view&iid=".$i."\"></a> ";

}
print $str;
}

this does however not work.. any ideas anyone?

emrys404

I can't say for sure the link will work but i do see some syntax errors. Try this:

$str .= "<a href=\"welcome.php?act=view&iid=$i\" target=\"mainFrame\">";

Roger_Ramjet

Better yet, try using a sensible string quoting syntax and strategy then you won't have to use all those escape characters

 $i=0;
$str='';
if (mysql_num_rows($numberresult)>0)
{
while ($row = mysql_fetch_array($numberresult, MYSQL_ASSOC))
{
$i++;
//$str .= $i.". ";
$str .= '<a href="welcome.php?act=view&iid=' .$i. '" target="mainFrame">';
$str .= '<img border="0" height="127" width="100" src="image1.php?act=view&iid=' .$i. '"></a>';

}
print $str;
}

Once you've got legible coding then you'll make less syntax errors and they'll be easier to spot when you do.

sander_ESP

ok, i got this part working.. thanks to you. it was indeed a syntax error.

however, what is still missing is that every photo has a unique person_ID. i need to transfer this from the left frame , into the mainframe.

i have chanched the code to this

if (mysql_num_rows($numberresult)>0) 
{ 

while ($row = mysql_fetch_array($numberresult, MYSQL_BOTH)) 
{ 
$person_ID=mysql_result($numberresult,$i,"person_ID");
$i++; 

$str .= '<a href="legend.php?act=view&iid=' .$i. '&person_ID=' .$person_ID. '" target="mainFrame">'; 
$str .= '<img border="0" height="127" width="100" src="image1.php?act=view&iid=' .$i. '"></a>'; 

} 
print $str; 
}

however now the person_ID has the same value as the iid, and that is not correct.

so photo one has iid= 1 and person_ID = 1 , but the person_ID beloning to the person on the first photo is not one, its 3.

any ideas?