[RESOLVED] New row every 3 entries.

[brendan2b]

Hello, I have a page for members with their photos. And right now I have a while loop displaying the images as a new row and cell per loop. I have tried creating other variables to create a way where I can put 3 pictures per row, and once there are 3 images, it creates a new row. I am struggling quite a bit. I think i need a nested while loop with a variable confirmation in the second loop telling it to exit when it reaches 3, but I have no idea.

Any advice would be most appreciated.

Thank you.

[Roger_Ramjet]

search these forums for 'loop control' and you'll find it all explained with full code examples - multiple times.

[brendan2b]

Hey thanks. Will do.

[scrupul0us]

post your code

[brendan2b]

$user_photos = mysql_fetch_array( $data );
print "<table width=800>";
$i=1;
$rows = mysql_fetch_array($user_photos);

while($user_photos / 3)

{

print "<tr>";
$j=0;

 while($user_photos = mysql_fetch_array( $data ) && $rows % == 0)
	{

$imagePath = "photos/$username/".$user_photos['imageThumbName'];
$imagePath2 = "http://www.photospooler.com/photos/$username/".$user_photos['imageThumbName'];
$imageName = $user_photos['imageName'];
$imageURL = "<a href='www.photospooler.com'><img src='$imagePath2' alt='www.photocooler.com'></a>";




print "<td align='center' valign='top' width=500><br>";
print "<span class='style6'><a href='rename.php?imageName=$imageName'>rename</a> | </span>";
print "<span class='style6'><a href='addToAlbum.php?imageName=$imageName'>add to public album</a> |  </span>";
print "<span class='style6'><a href='addToAlbum.php?imageName=$imageName'>delete</a></span>";
print "<br><br><img src='$imagePath'><br><br>";
print "<span class='style6'>email, IM, link to share with friends</span><br>";
print "<input type='text' name='image$i' value='http://www.photospooler.com/photos/$username/$imageName' readonly='readonly'><br><br>";
print "<span class='style6'>HTML code, for myspace or facebook</span>";
print "<input type='text' name='image$i' value='$imageURL'><br><br>";
print "<span class='style6'>BB code, forums</span>";
print "<input type='text' name='image$i' value='[IMG]http://photospooler.com/photos/$username/$imageName'>";
print "</td>";




$i=$i+1;
}
$j=$j+1;


}
print "</table>";

Here is my code. I was in the process of researching and trying to figure this out. Hopefully you have some pointers. Also, how do I go about getting the value inside the first textfield. The value is in HTML and for somereason it posts the image instead of the text inside the text box. Thanks again.

Brendan

[scrupul0us]

after $i=$i+1;

insert:

if ($i%3 == 0)
{
print "<br/>";
}

[intenz]

Something like this...?

<?php
$array = array( 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i' );

$i = 0; $j = 0;
while( $j < count( $array ) )
{	
	echo $array[$j];

$i++;

if( $i < 3 )
	echo ' ';

if( $i == 3 )
{
	echo '<br />';
	$i = 0;
}

$j++;
}
?>

[brendan2b]

Yes exactly. Much appreciation. Thank you.

[intenz]

No problem.

[intenz]

Please mark this thread as RESOLVED if it's resolved. 🙂