get the newest three images in a directory

[scrupul0us]

i'm looking to display the newest 3 images in a directory based on a date stamp:

date("F d Y H:i:s.",filemtime('bv.gif'));

not really sure where to start

[bradgrafelman]

Something like:

function getImages($dir, $num=3) {
	if(!is_dir($dir))
		return FALSE;
	elseif($dir{(strlen($dir)-1)} != '/')
		$dir .= '/';

$files = array();
foreach(glob($dir . '*') as $file) {
	$files[$file] = filemtime($file);
}

arsort($files);
$files = array_slice($files, 0, $num);
return $files;
}

perhaps? Pretty straightforward... feel free to ask if you don't understand what I did.

EDIT: Code edited to return the files' modified times. The returned value of this function is either FALSE (first argument passed wasn't a directory) or an array consiting of the name of the file as a key and its value being the file's modified time. But of course, you can always see this visually using [man]print_r/man...

[scrupul0us]

awesome... ill toy with it when i get home tonight... it looks like that will do nicely