imagejpg question

[badzv]

hi guys...got some questions regarding on my script....

<?php

error_reporting(0);

$w = (int)$_POST['width'];
$h = (int)$_POST['height'];

$img = imagecreatetruecolor($w, $h);

imagefill($img, 0, 0, 0xFFFFFF);

$rows = 0;
$cols = 0;

for($rows = 0; $rows < $h; $rows++){

$c_row = explode(",", $_POST['px' . $rows]);
for($cols = 0; $cols < $w; $cols++){

	$value = $c_row[$cols];

	if($value != ""){

		$hex = $value;
		while(strlen($hex) < 6){
			$hex = "0" . $hex;
		}

		$r = hexdec(substr($hex, 0, 2));
		$g = hexdec(substr($hex, 2, 2));
		$b = hexdec(substr($hex, 4, 2));

		$test = imagecolorallocate($img, $r, $g, $b);

		imagesetpixel($img, $cols, $rows, $test);
	}
}
}

header("Content-type:image/jpeg");

imagejpeg($img, "", 95);

?>

...as you can see, the image comes from a POST variables. the problem here is that the image could be viewed but its not on the server. could somebody help me please how to make that image thats been generated with my php script to be on the server already? upon generated, it would be on the server already.

thank you very much!

[Kudose]

You need to save the image.

$data = imagejpeg($img, "", 95);
$handle = fopen("myImage.jpg", "rb");
fwrite($handle, $data);
fclose($handle);

[badzv]

Kudose wrote:

You need to save the image.

$data = imagejpeg($img, "", 95);
$handle = fopen("myImage.jpg", "rb");
fwrite($handle, $data);
fclose($handle);

sir, would it be ok if you could elaborate to me the code? im kinda new to php. and whats the "rb" in fopen ?

thanks for the reply!

[Kudose]

I screwed up, it should be fopen('myImage.php', 'wb')

[bradgrafelman]

If you're talking about saving the image as a file, all you need to do is change this:

imagejpeg($img, "", 95);

to something like this:

imagejpeg($img, 'path/to/image.jpg', 95);

Looking at the manual for [man]imagejpeg/man, you'll see that the second argument is a filename.