[RESOLVED] help with an IF statement to show content of a field if NOT empyty

[mars16]

Can someone help me write the syntax for an IF statment to show the content of a database field if NOT empty?

my field is called name. how do you say NOT empty in php.

if $row["name"] NOT EMPTY then
echo ($row["name"]);

[Piranha]

if (!empty($row['name']))
{
    // do something
}

[mars16]

Thnx Piranha.

[bradgrafelman]

Don't forget to mark this thread resolved.

[NogDog]

While empty() is convenient and may well be all you need to use here, I feel it necessary to point out that in certain situations it may not respond as needed, depending on your data and what you consider to be "empty":

<?php
$testData = array('space' => ' ', 'zero' => 0, 'zeroStr' => '0');
foreach($testData as $key => $val)
{
   printf("<p>Value of empty() for '%s': %s</p>\n", $key, var_export(empty($val),1));
}
?>

Output:

Value of empty() for 'space': false
Value of empty() for 'zero': true
Value of empty() for 'zeroStr': true

If you only want to match on an empty string (and not any value of zero), then you should use:

if($row['name'] !== '') {    // note the use of !== rather than !=

Or if you want to treat a value that is all white-space as also being 'empty':

if(trim($row['name']) !== '') {    // note the use of !== rather than !=