[RESOLVED] using include with params

[kohan]

Hello I am new to PHP so any help would be great

I am trying to call up another php file with a paramenter

ie. include "a.php?id=2";

however nothing shows up from it, I have checked the files and ran them..so no syntax errors..

I am thinking perhaps its some settings in php.ini?

btw, I am using
php5.2
apache2.2.4

thanks for the hlep

[Houdini]

Show more code then you might get some help.

[NogDog]

Include would try to read a file named "a.php?id=2", and as there presumably is no such file, nothing happens. (Depending on your error_reporting and display_errors settings, you might get an error message.) Include normally reads the text of the specified file and processes it as if it were actually in the calling file at that point. If you want the included file to actually be processed separately and recognize the URL query string, then you might be able to call it as a full URI, depending on your URL_fopen_wrappers settings.

include 'http://localhost/a.php?id=2';

[MarkR]

Don't do that.

Include is not supposed to take parameters, nor are you supposed to use globals as parameters to includes (although that does work).

Instead, put your code in a function with parameters and call the function.

That's how it's supposed to work.

On no account include() a URL. It doesn't do what you want and probably won't work anyway*

Mark

• As of PHP 5.2, where including URLs is disabled by default, as it's plain WRONG.

[kohan]

I understand that these codes are short, but I am testing it out for a larger file.
so here is the sample file i am trying to call on..
b.php -->
<?php
$result = $_GET[result];
if ($result == 0)
echo "ADFASDF";
else if ($result ==1)
echo"adfasdf";
?>

in the original file I want to pass in the parameter
such as in the case if I need to print out result 0 or result 1
a.php-->
<?php
echo "this is from 0 ";
include "b.php?result=0";
echo"<br>;
echo"this is from 1";
include "b.php?result=0";
?>

MarkR wrote:

Don't do that.

Include is not supposed to take parameters, nor are you supposed to use globals as parameters to includes (although that does work).

Instead, put your code in a function with parameters and call the function.

That's how it's supposed to work.

On no account include() a URL. It doesn't do what you want and probably won't work anyway*

Mark

• As of PHP 5.2, where including URLs is disabled by default, as it's plain WRONG.

so how do I write such a function?
Thanks for the help I really appreciate it

[NogDog]

b.php:

<?php
function b($result)
{
   if ($result == 0)
      echo "ADFASDF";
   else if ($result ==1)
      echo"adfasdf";
}
?>

a.php:

<?php
include "b.php";
echo "<p>This is from 0: " . b(0) . "</p>\n";
echo "<p>This is from 1: " . b(1) . "</p>\n";
?>

[kohan]

ok great that works.. thanks you guys

[bradgrafelman]

Don't forget to mark this thread resolved.